The slope, or change in y over change in x, would be -2.
The y-intercept would be (0,-3)
Plot the point (0,-3)
Count over one to the right, and two down. Plot another point (1,-5)
Count over one to the right, and two down. Plot another point (2,-7).
Continue doing this, and then connect the points to form a line.
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
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f(x)=2X-2
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You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
Yes, that is a shifted tanX graph, just as you would shift any graft.
2,4
-2
-2
-2x plus 3y equals 1
y=2x means that the line on the graph will travel through the coordinates (0,0) (2,1) (4,2) (6,3) etc. Basically it will go up 2x's for every 1y.y=2x is a linear function.
y = 2x + 5x - 12 = 7x - 12 So the zero is 12/7 = 1.7143 (approx)
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f(x)=2X-2
The derivative of a function is the function's tangent function.So, d(y)/dx = d(2tan(2x))/dx = 2*d(tan(2x))/dx = 2*d(tan(u))/du*du/dx, where u=2x, = 2*sec2(2x)*d(2x)/dx = 4*sec2(2x)*d(x)/dx = 4*sec2(2x)Now just make a plot for y = 4*sec2(2x) and you got your tangent function.
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