53 - 1 or 1 chance in 54 or 0.0185 or 1.85%
The event space comprises the numbers 10 to 99, 90 such numbers. The favourable events are 15, 21, 27, ... , 99. There are 15 such numbers. So the probability is 15/90 = 1/6
To find the probability of selecting a number from 20 to 30 that is divisible by 3, we first identify the numbers in that range: 21, 24, 27, and 30. There are four suitable candidates, so the probability of selecting one of them is 4 out of 11 (the total numbers from 20 to 30, inclusive). After replacing the selected number, we check which of these are divisible by 12. Among the numbers listed, only 24 is divisible by 12. Therefore, the probability of selecting a number divisible by 3 and then finding it divisible by 12 is 1 out of 11, which simplifies to approximately 0.0909 or 9.09%.
The probability is(the total number of numbers on the spinner minus 5)/(the total number of numbers on the spinner)Another way to express the same probability is1 - 5/(the total number of numbers on the spinner)
The probability of spinning the number 3, or any number, is 1/4 or 0.25 since there is 4 numbers total.
On the basis that numbers are a continuous variable, the probability of any particular number (or pair) is 0.
10
The probability of selecting a 17 (or any number for that matter) is 1/20 or .05 or 5%.
The event space comprises the numbers 10 to 99, 90 such numbers. The favourable events are 15, 21, 27, ... , 99. There are 15 such numbers. So the probability is 15/90 = 1/6
To find the probability of selecting a number from 20 to 30 that is divisible by 3, we first identify the numbers in that range: 21, 24, 27, and 30. There are four suitable candidates, so the probability of selecting one of them is 4 out of 11 (the total numbers from 20 to 30, inclusive). After replacing the selected number, we check which of these are divisible by 12. Among the numbers listed, only 24 is divisible by 12. Therefore, the probability of selecting a number divisible by 3 and then finding it divisible by 12 is 1 out of 11, which simplifies to approximately 0.0909 or 9.09%.
The probability is(the total number of numbers on the spinner minus 5)/(the total number of numbers on the spinner)Another way to express the same probability is1 - 5/(the total number of numbers on the spinner)
The probability is 1/b.
The probability is 0.
The probability of spinning the number 3, or any number, is 1/4 or 0.25 since there is 4 numbers total.
On the basis that numbers are a continuous variable, the probability of any particular number (or pair) is 0.
You carry out an experiment repeatedly. Then the number of times that the selected even occurs divided by the total number of trials is the relative probability for that event.
The prime numbers from one to nine are 2, 3, 5, and 7. There are nine numbers from one to nine. The probability is 4 (the number of prime numbers) over 9 (the total number of numbers). Therefore, the probability of choosing a prime number is 4/9 or about 44 percent.
The probability of spinning the spinner and landing on an odd number depends on the number of odd numbers on the spinner and the total number of numbers on the spinner. If there are 3 odd numbers on the spinner and a total of 6 numbers, then the probability of landing on an odd number is 3/6, which simplifies to 1/2 or 50%.