False
Then the radius bisects the chord.
a chord
A chord.
A straight line that intersects a circle's circumference at two points will create a chord of which the circle's diameter is its largest chord.
Imagine if you will a circle with a chord drawn through it and a line running from the center of that chord to the center of the circle. That line is necessarily perpendicular to the chord. This means you have a right triangle whose hypotenuse is the radius of the circle. The radius is thus given by: r = sqrt{(1/2 chord length)^2 + (length of perpendicular line)^2} The actual formula to find the radius is as follows: r= C squared/8a + a/2, where C is the chord length, and a is the distance from center point of the chord to the circle , and a and C form an angle of 90 degrees. the entire formula before simplification is r = sqrt {(1/2 C)^2 + (r-a)^2}
If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.
The radius of the circle that is perpendicular to a chord intersects the chord at its midpoint, so it is said to bisect the chord.
its false
Then the radius bisects the chord.
Bisects
Perpendicular.
False
Bisects that chord
A Chord. Or another radius!
YesAt a right angle
A chord line intersects a circle at two points of which the circle's diameter is its largest chord.
true, because both distances of the chord are congruent