This is an algebra problem.
Let's call the length L and the width W
L = 3W + 8 is an equation describing the first part of the problem
2L + 2W = 64 is an equation describing the second part of the problem.
Now, lets substitute the (2L) in the second equation with twice the value of L in the first equation
2(3W + 8) + 2W = 64, and now we'll work out the contents of the brackets.
6W + 16 + 2W = 64, now add the values of W
8W + 16 = 64, now bring all the numeric values to the same side of the equation
8W = 64 - 16
8W = 48, now divide both sides by 8
W = 6
Now we can substitute 6 for W in the first equation
L = 3(6) + 8, now we'll work out the contents of the brackets
L = 18 + 8 now we'll add the numbers
L = 26
So now we have two values and we need to ensure that they add up to 64
2(26) + 2(6) = 52 + 12 = 64
So, the rectangle is 26 x 6
The area is the length times the width. The perimeter is two times the length plus two times the width.
15 feet.
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
2 times length plus 2 times width = perimeterhalf the perimeter of a rectangle
64 meters
18.4cm by 22.4cm
8X36
To find the perimeter of a rectangle, you use the formula (P = 2 \times (length + width)). For a rectangle with dimensions 9 and 13, the perimeter is (P = 2 \times (9 + 13) = 2 \times 22 = 44). Thus, the perimeter is 44 units.
To find the dimensions of the rectangle, we need to set up equations based on the given area and perimeter. The area of a rectangle is length multiplied by width, so length times width equals 12 cm. The perimeter of a rectangle is given by the formula 2(length + width), which in this case equals 16 cm. By solving these two equations simultaneously, we can find the dimensions of the rectangle.
That would be 3 x 9 inches.
2 times (length + width)
Area is length times width, perimeter is twice the sum of length and breadth.
The perimeter of a rectangle is calculated using the formula ( P = 2 \times (length + width) ). For a rectangle with a length of 30 meters and a width of 20 meters, the perimeter would be ( P = 2 \times (30 + 20) = 2 \times 50 = 100 ) meters. Thus, the perimeter of the rectangle is 100 meters.
the length is equal to 160,083
The area is the length times the width. The perimeter is two times the length plus two times the width.
length times width
The perimeter of a rectangle is given by (2L plus 2W). If you double either the width or length dimension, then it is four times the original dimension, such as (4L plus 2W) or (2L plus 4W).