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Earn +20 ptsQ: Integration of cos 5x
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Integration of sinx is?
-cos x + C
If y equals the integral from 5x on top to cosx on bottom of cos of u squared du what is y'?
y=S^5x _cos(x) cos(u²) du The derivative of a definite integral of a function f(x) is equal to the difference in the product of the function at each limit of integration times the limit of integration. y'=cos(u²)*du/dx from u=cos(x) to u=5x y'=-sin(x)*cos(cos(x)²)-5*cos(25x²) To understand why this works, consider the following where F(x) is the antiderivative of f(x) y=F(g(x))-F(h(x))=S f(x)dx from h(x) to g(x) If you take the derivative of this expression and apply the chain rule dy/dx = dF(g(x))/dx - dF(h(x))/dx = f(g(x))*dg/dx - f(h(x))*dh/dx
What is the answer to 5x plus 5x-10?
5x+5x-10 10x-10 is the only answer you can get from this
What is 10x minus 5x plus 5x?
10x - 5x + 5x = 10x
-10x plus 5x?
-10x + 5x = -5x
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