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yes the answer to 1 divided by 3 = 1/3 (this is 1 third)

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16y ago

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Are all numbers divisible by -3 divisible by 3?

No, just every third one.


Explain why the product of any four consecutive integers is divisible by 24?

At least one of the four will be divisible by 4. One other will be divisible by 2 (but not by 4) One other will be divisible by 3. Hence the product will be divisible by 4 x 2 x 3 = 24.


Is 5193 a prime number?

No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.


What is 15345 divisible by?

3 is one factor.


How many times is 34 divisible by 2 and 3?

34 is divisible by 2 seventeen times. 34 is divisible by 3 eleven times with one left over.


Why is 149 not divisble by 3?

One way to work it out in your head is to consider than 30 is divisible by 3, so you can ask if 140 is divisible by 30. It's not, since 14 is not divisible by 3. If the number was 129 or 159, both of those are divisible by three since both 12 and 15 are divisible by 3.


Is 345456543 a prime number?

No, this number is divisible by 3 and hence is not a prime number. You can tell that fast by adding the individual digits. If that sum is itself divisible by 3, as this one is, then the number itself is divisible by 3.


What is the smallest number consisting of only zeros's and one's that is divisible by fifteen?

To be divisible by 15, it must also be divisible by 3 and by 5. To be divisible by 3, the sum of the digits must be divisible by 3; to be divisible by 5, the number must end with a zero or a five. Considering all these criteria, I guess that number would be 1110.


If x is an integer divisible by 3 then is x2 divisible by 3?

Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.


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Why is the product of 3 consecutive integers always divisible by 6?

Let the three integers be, n, (n + 1), and (n + 2) Then at least one of these numbers is even and therefore has a factor of 2. And one of the numbers is divisible by 3 **. Therefore the product has factors of 2 and 3 and is thus divisible by 2 x 3 = 6. ** Either n is divisible by 3. Or, n leaves a remainder of 1 when divided by 3 in which case (n + 2) is divisible by 3. Or, n leaves a remainder of 2 when divided by 3 in which case (n + 1) is divisible by 3.


Is 710 divisible by 2 3 5 9 or 10?

Check your divisibility rules: 2: One's digit is an even number YES 3: The sum of the digits is divisible by 3 NO: 7 + 1 + 0 = 8 which is not divisible by 3 5: One's digit is a 5 or a 0 YES 9: The sum of the digits is divisible by 9 NO: 7 + 1 + 0 = 8 which is not divisible by 9 10: One's digit is a 0 YES