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How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
What line Is perpendicular to 3x-y5 and whose y-intercept is -7?
If you mean: 3x-y=5 then y=3x-5 and the perpendicular equation is y=-1/3x-7
What is the slope of the perpendicular to the line whose equation is y equals 5x-7?
12
What is the perpendicular ditance from the point 7 5 to the line 3x plus 4y -16 equals 0?
If you mean the perpendicular distance from the coordinate of (7, 5) to the straight line 3x+4y-16 = 0 then it works out as 5 units.
What is the perpendicular bisector equation to the line segment of -1 -6 and 5 -8?
Points: (-1, -6) and (5, -8) Midpoint: (2, -7) Perpendicular slope: 3 Perpendicular bisector equation: y = 3x -13
Is x plus 2y equal 7 and 2x plus 4y equals 3 perpendicular?
No. They are parallel.
How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
What is the slope of all lines perpendicular to the line y equals 7?
All parallel lines have a zero slope.
What is the perpendicular bisector equation of the line segment whose end points are at 3 5 and 7 7?
End points: (3, 5) and (7, 7) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Perpendicular bisector equation: y-6 = -2(x-5) => y = -2x+16
What is perpendicular to y equals 5x-2?
7
What line Is perpendicular to 3x-y5 and whose y-intercept is -7?
If you mean: 3x-y=5 then y=3x-5 and the perpendicular equation is y=-1/3x-7
What is the perpendicular bisector equation meeting the line segment of 3 5 and 7 7?
Line segment: (3, 5) and (7, 7) Midpoint: (3+7)/2, (5+7)/2 = (5, 6) Slope or gradient: (7-5)/(7-3) = 1/2 Perpendicular slope = -2 Equation: y -6 = -2(x-5) => y = -2x+10+6 => y = -2x+16 So the perpendicular bisector equation is y = -2x+16
What is the slope of the perpendicular to the line whose equation is y equals 5x-7?
12
What is the perpendicular bisector equation passing through the line segment of 7 7 and 3 5 giving brief details?
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
What is the perpendicular ditance from the point 7 5 to the line 3x plus 4y -16 equals 0?
If you mean the perpendicular distance from the coordinate of (7, 5) to the straight line 3x+4y-16 = 0 then it works out as 5 units.
What is the slope of every line perpendicular to the graph of this equation 4x plus 5y equals 7?
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
What is the perpendicular bisector equation to the line segment of -1 -6 and 5 -8?
Points: (-1, -6) and (5, -8) Midpoint: (2, -7) Perpendicular slope: 3 Perpendicular bisector equation: y = 3x -13
