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Q: Log 4 64 equals y

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-8x-8y=-64 -8y=8x-64 y=-x+8

You already know the value of x is 4. To solve the value of y = 64x, mutlply 64 x 4. Hence, y = 64*4 = 256.

x = 2 so x squared = 4 and 2x squared = 2 times 4 = 8; y = 4 so xy = 2 times 4 = 8 and 3xy = 3 times 8 = 24; y squared = 4 times 4 = 16 and 4y squared = 4 times 16 = 64; so 8 + 24 - 64 = 32 - 64 = -32

Evaluate x/y when x = 4 and y = 4. x/y = 4/4 = 1/1 = 1

x = 8y = -42x - y = 2(8) - (-4) = 16 + 4 = 20

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8x8 = 64 so it is 64 (the y) 3x4 = 12 so it is 12 (the x) 64+12 is 76.

y = 10 y = log x (the base of the log is 10, common logarithm) 10 = log x so that, 10^10 = x 10,000,000,000 = x

find x3+y2 if x=4 and y=3 ( 4*4*4)+(3*3) 64 +9 =73

let Y be the number you want. Then Y / -4 = 64 => Y = 64 x -4 = -256

If y=8, then 8 squared is 64.

-8x-8y=-64 -8y=8x-64 y=-x+8

"Log" is not a normal variable, it stands for the logarithm function.log (a.b)=log a+log blog(a/b)=log a-log blog (a)^n= n log a

b y = xlog(b) + log(y) = log(x)

x = 2, y = 84x + 8y= 4(2) + 8(8)= 8 + 64= 72

You have, y = 6 + log x anti log of it, 10y = (106) x

y=logx becomes 10^y=x

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