8
y2 - 16y + 64 = 0 (y - 8)2 = 0 y - 8 = 0 y = 8
8
Yes, as x-y2=0
find x3+y2 if x=4 and y=3 ( 4*4*4)+(3*3) 64 +9 =73
8
y2 - 16y + 64 = 0 (y - 8)2 = 0 y - 8 = 0 y = 8
8
That's the equation of a circle with its center at the origin and a radius of 8.
y2 - 64 can be written as y2 - 82, which is of the form of a2 - b2.And a2 - b2 is factored as (a-b)(a+b).Therefore, y2 - 64 is factored as (y+8)(y-8).
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
(x-2)^2+y^2=64
Yes, as x-y2=0
8
y2 = 4ax is as broken down it can get because there are no like terms that can be combined.
find x3+y2 if x=4 and y=3 ( 4*4*4)+(3*3) 64 +9 =73
x2 + y2 = 2r2