y-(y_1)=m(x-x_1)
(x_1,y_1) is the specified point on your line
and "m" is the slope of your line.
Hope this helps!! ^^
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Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
You use point-slope form to find the equation of a line if you only have a point and a slope or if you are just given two point. Usually you will convert point-slope form to slope-intercept form to make it easier to use.
Point slope form of y-7=-3x identifies the line that pass through the slope of line (-2 -5) (7 -6).
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
Slope intercept form is y = mx + b. Point slope form is y - y1 = m(x - x1). Here is an example of changing slope-intercept form to point-slope form: Change y = 3x + 2 to point slope form: y = 3x + 2 Subtract 2 from each side: y -2 = 3x The equation y-2 = 3x is in point-slope form. It can be rewritten as y-2 = 3(x-0), showing that the line passes through the point (0,2), but is doesn't need to be. (The x1 and y1 represent one point on the line, it doesn't matter which one. Therefore, there are many different equations for the same line in point-slope form. For example, the equation y -2 = 3x is the same line as the equation y - 11 = 3(x - 3), which is the same line as the equation y + 4 = 3(x + 2).)