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How solve a second grade equation?
Y+6=18÷2
How do you solve 14 equals 18 plus y?
U can subtract 18 from each side of the equation.
How do you solve y-4x 1?
How do you solve y=-4x+1
Which equation could be used to solve y 2 7y18 by factoring?
What are the mathemtical signs????? Is it y^2 + 7y - 18 This factors to ( y - 2)(y + 9) or y^2 - 7y - 18 (y + 2)(y - 9)
What two numbers add up to 33 and when you subtract them they equal 15?
48
What is the answer to -23y-18-5y?
Total solution depends on the value of y. -18y-18 or -18(y+1)
How do you factor -6y plus 23y plus 4?
As written, that's 17y + 4 which is in its simplest form. -6y^2 + 23y + 4 factors to (4 - y)(1 + 6y)
What should be added to both sides of this equation to solve for the variable 18 plus y equals 32?
You add -18... 18 + y = 32 18 + y + (-18) = 32 + (-18) y = 14
What equation could be used to solve y² plus 7y equals 18 by factoring?
y2+7y=18 y2+7y-18=0 (y+9)(y-2)=0 y=-9 & y=2
How solve a second grade equation?
Y+6=18÷2
Solve for y 5x 6y 18?
That's not an equation, it is not solveable.
Solve this system of equations using substitution. Put your answer in ordered pair form (x y). x plus 7y 39 3x - 2y 2?
To solve the system of equations given by ( x + 7y = 39 ) and ( 3x - 2y = 2 ) using substitution, we can first solve the first equation for ( x ): ( x = 39 - 7y ). Substituting this into the second equation gives ( 3(39 - 7y) - 2y = 2 ). Simplifying this results in ( 117 - 21y - 2y = 2 ), or ( 117 - 23y = 2 ), leading to ( 23y = 115 ) and ( y = 5 ). Plugging ( y = 5 ) back into ( x = 39 - 7(5) ) gives ( x = 4 ). Thus, the solution in ordered pair form is ( (4, 5) ).
How do you solve y plus y plus 2 equals 18?
y + y + 2 = 182y + 2 = 182y = 16y = 8whew !
How do you solve 14 equals 18 plus y?
U can subtract 18 from each side of the equation.
6x-18y plus 108 equals 0 solve for y?
6x +108=18y y=6x/18+108/18 y=x/3+6
What are the possible values of x and y when 29x plus 23y equals 23.29 showing work in detail?
In this type of problem let the numerator of a fraction be 23.29 and its denominator be twice the coefficient of the variables and so:- 29*(23.29/58)+23*(23.29/46) = 23.29 Therefore the possible values of x and y are 23.29/58 and 23.29/46 respectively
What should be added to both sides of this equation to solve for the variable18 plus y equals 32?
18+y=32 y=14
