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'W' and 'L' are independent variables.
'P' is the dependent variable.
'2' and '2' are the constants.
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∙ 12y ago
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Solve for w 2l plus 2w equals P?
2l + 2w = P Subtract 2l from both sides: 2w = P - 2l Divide both sides by 2: w = P/2 - l
Write the perimeter of a rectangle?
p=2l+2w
The formula for the perimeter of a rectangle is P equals 2W plus 2L with perimitor of 100 length 30?
P = 100 l = 30 w = 20
What is w if 2w equals 16?
what is w if 2w = 16
The formula for the perimeter of a rectangle is P equals 2l plus 2w where l is the lengty and w is the width a rectangle has a permeter of 24 inches find its dimensions if its length is 3 in greater?
39
Solve for w 2l plus 2w equals P?
2l + 2w = P Subtract 2l from both sides: 2w = P - 2l Divide both sides by 2: w = P/2 - l
What eqations represents the formula for perimiter of a rectangle p equals 2l plus 2w solve for l?
2L+2W=P (S2w) Subtract 2W from both sides 2L=P-2W (D2) Divide both sides by 2 L=(P-2W)/2
If P equals 2L - 2W solve for L if P equals 40 and W equals 2?
22
The length of rectangle is 5 less than twice the width The perimeter of the rectangle is 80. Find the dimensions of the rectangle?
L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15 L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15
How do you solve questions like P2L 2W solve for W?
First, I am assuming you mean P = 2L + 2W, solve for W. If so, then see below! You solve equations the same way, whether they have multiple variables or not: Distribute, Combine Like Terms, Move the variable you are isolating to one side, Add or Subtract, then Multiply or Divide. Let's show how this equation is very much like an equation having only one variable: 28 = 20 + 2W -20 -20 8 = 2W ÷2 ÷2 4 = W So, if you get stuck, just "fake" the variables you aren't solving for into being random numbers. Solve your "fake" equation like you would any equation. Then use the same steps in your original "variable" equation. P = 2L + 2W -2L -2L P-2L= 2W ÷2 ÷2 (P-2L)/2 = W
What is the formula for perimeter of a rectangle?
For a rectangle, P = 2L + 2W (L is length, W is width)
Formula for length of a rectangle?
a = L x W: area equals length times the width. p = 2L + 2W: perimeter equals 2 times the length plus 2 times the width so L = (p - 2W)/2
Work this problem Given P equals 2l plus 2w close parenthesis solve for B Put answer in form of isolated variable formula?
There is no indication as to what B represents and consequently no possibility of answering the question.
Write the perimeter of a rectangle?
p=2l+2w
What are some math formulas?
p=2l+2w
How do you find the perimeter on the dimensions of rectangles?
2l+2w
What is the perimeter of rectangle formula?
P=2w+2l
