x2 - x = 20 x2 - x - 20 = 0 (x - 5)(x + 4) = 0 x - 5 = 0 and x + 4 = 0 So, x = 5 ans x = -4
x: x2 - 81 = 0
Divide both sides of the equation by x: x2 = 9x x2 / x = 9x / x x = 9
x - x2 - 9x + 14 = 0 ; whence, x2 + 8x = 14 , x2 + 8x + 16 = 30 , and x + 4 = ±√30 . Therefore, x = ±√30 - 4 .
x2 + 20x +0 =30 [(20/2)2 =100] x2 + 20x + 100 =30 +100 √(x+10)2=√130 x+10=√130 x= −10+√130 √ means square root
x2 - x = 20 x2 - x - 20 = 0 (x - 5)(x + 4) = 0 x - 5 = 0 and x + 4 = 0 So, x = 5 ans x = -4
x=18
x: x2 - 81 = 0
Divide both sides of the equation by x: x2 = 9x x2 / x = 9x / x x = 9
144X = X2 144X - X2 = 0 (144 - X)X = 0 X = 0 or X = 144
20/x2 -1/x = 1 Multiply all terms by x2: 20 -x = x2 Subtract x2 from both sides: 20 -x -x2 = 0 Divide all terms by -1 and form a quadratic equation: x2+x-20 = 0 Factor the equation: (x+5)(x-4) = 0 Solution: x = -5 or x = 4
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
x = +13x = - 13
Assuming that by writing that equation as a question, you mean to ask how to solve it for x, that can be done as follows: x2 + 4x - 6 = 0 x2 + 4x + 4 = 10 (x + 2)2 = 10 x + 2 = √20 x = -2 ± √20
x2-12x+20=0you can factor this equation into:(x-10)(x-2)=0set each factor equal to zero & solve for x to get:x=10 & x=2
x2+16x-80 = 0 (x-4)(x+20) = 0 x = 4 or x = -20
You cannot, in general, solve one equation with two unknown variables. x - y = x - x2 Subtract x from both sides: - y = - x2 Change signs: y = x2 And that is as far as you can go.