If necessary, rearrange the linear equation so that it is in the slope-intercept form: y = mx + c Then the gradient of the line is m.
y = -4x
y = 2x + 3
. the equation of a straight line can be found by using two points on a line . First find the gradient of the line using the gradient formula . now substitute the gradient into general form replacing "m" . use one of the points and substitute into equation to solve "c" example 1: find the equation of the line which passes through the points (1,3) and (2,5). step 1: find the gradient M=5-3/2-1=2 (/=divide) step 2: place m into the equation Y=2x+c step 3: substitute point into equation 3=2(1)+c step 4: solve C=1 equation is Y=2x+1 hope that helps :)
When the equation is given in the standard form: y = mx + c, the gradient is m. So here, y = 7x + 2 means m, the gradient, is 7.
An equation such as y = mx + c is said to be in standard form. From such an equation, Gradient = coefficient of x = 3
Gradient= change in field value divided by the distance
If necessary, rearrange the linear equation so that it is in the slope-intercept form: y = mx + c Then the gradient of the line is m.
It's 2. your equation is y=mx+b, so the gradient, or slope, is the "m" in the equation.
10
If you have the equation, yes. If the equation is given in terms of x and y, make y the subject of the equation. That is, expres the equation in the form y = mx + c where m and c are constants. Then the gradient is m.
15
y = 11x + 5 The slope/gradient of this equation is 11. The slope/gradient can easily been seen in a linear equation: it is simply the co-efficient of x
1
Change the number in front of the X, as that is the gradient.
y = -4x
Slope or gradient = (y2-y1)/(x2-x1)