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What three consecutive numbers have a product of 210?
5*6*7 = 210
Three consecutive numbers have the sum of 210 what are the numbers?
The numbers are 69, 70, and 71.
The product of two consecutive integers is 210?
You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210
The product of three consecutive whole numbers is 210 what is the?
(x)(x + 1)(x + 2) = 210 (x^2 + x)(x + 2) = 210 x^3 + 2x^2 + x^2 + 2x = 210 x^3 + 3x^2 + 2x = 210 x^3 + 3x^2 + 2x - 210 = 0 Let's try 5, as a factor of 210. 5] 1 3 2 -210 5 40 -210 ---- 8 42 0 remainder, so 5 is a root. Since 5 is a root of the equation, let say that 5 is the first number. So, the second number is 6, and the third number is 7. Check: 5 x 6 x 7 = 210
What is the square root of 210 simplified?
210 = 2*105 = 2*3*35 = 2*3*5*7. To simplify sqrt(210) you need a pair of factors to form a square. You can then take out the square root, which will be a whole number. Since 210 has no pair of factors, sqrt(210) cannot be simplified.
What three consecutive numbers have a product of 210?
5*6*7 = 210
The product of two consecutive numbers is 210 What are the numbers?
They are 14 and 15.
What Two consecutive numbers with product 210?
The numbers are 14 and 15.
Can you find the 2 consecutive numbers with a product of 702 and 210?
702 = 26 x 27; 210 = 14 x 15.
What three consecutive numbers equals 210?
The numbers are 69, 70 and 71.
Three consecutive numbers have the sum of 210 what are the numbers?
The numbers are 69, 70, and 71.
The product of two consecutive integers is 210?
You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210
How do you calculate the least common multiple of 2 consecutive numbers that is greater than 200 and a multiple of 7?
Consecutive numbers can't both be multiples of 7. The LCM of consecutive numbers is their product. 14 and 15 are consecutive numbers whose LCM is a multiple of 7 that is greater than 200.
Product of three concecutive integer is 210 then find the sum of smallest two integers?
Let's assume that the three consecutive integers are n-1, n, and n+1. We know that their product is 210, so we can set up the equation (n-1)(n)(n+1) = 210. By solving this equation, we can find that the three integers are 6, 7, and 8. Therefore, the sum of the smallest two integers is 6 + 7 = 13.
How you will get 210 by mulitiplying 2 consecutive numbers?
14 x 15 = 210
The product of three consecutive whole numbers is 210 what is the?
(x)(x + 1)(x + 2) = 210 (x^2 + x)(x + 2) = 210 x^3 + 2x^2 + x^2 + 2x = 210 x^3 + 3x^2 + 2x = 210 x^3 + 3x^2 + 2x - 210 = 0 Let's try 5, as a factor of 210. 5] 1 3 2 -210 5 40 -210 ---- 8 42 0 remainder, so 5 is a root. Since 5 is a root of the equation, let say that 5 is the first number. So, the second number is 6, and the third number is 7. Check: 5 x 6 x 7 = 210
What consecutive numbers equal 421?
210 and 211
