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(x)(x + 1)(x + 2) = 210

(x^2 + x)(x + 2) = 210

x^3 + 2x^2 + x^2 + 2x = 210

x^3 + 3x^2 + 2x = 210

x^3 + 3x^2 + 2x - 210 = 0

Let's try 5, as a factor of 210.

5] 1 3 2 -210

5 40 -210

---- 8 42 0 remainder, so 5 is a root.

Since 5 is a root of the equation, let say that 5 is the first number. So, the second number is 6, and the third number is 7.

Check:

5 x 6 x 7 = 210

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