X= 1.567764363, -9.567764363
If: x2+x = 12 Then: x2+x-12 = 0 And using the quadratic formula: x = -4 or x = 3
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
Solve using the quadratic formula
For any quadratic ax2 + bx + c = 0 we can find x by using the quadratic formulae: the quadratic formula is... [-b +- sqrt(b2 - 4(a)(c)) ] / 2a
It is a quadratic equation and its solutions can be found by using the quadratic equation formula.
If: x2+x = 12 Then: x2+x-12 = 0 And using the quadratic formula: x = -4 or x = 3
5x^(2) + 2x - 4 = 2x^(2) Hence 3x^(2) + 2x - 4 = 0 Now apply the Quadratic Equation. x = { - 2 +/- sqrt[2^(2) - 4(3)(-4)]} / 2(3) x = {-2 +/- sqrt[4 + 48]} / 6 x = { -2 +/- sqrt(50_] / 6 x = { -2 +/-5sqrt(2)} / 6 x = (-2 - 5sqrt(2))/ 6 & x = (-2 + 5sqrt(2))/ 6 Since the square root of '2' is an Irrational Number. (decimals go to infinity, the answer is left in 'surd' form .
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
Using the quadratic equation formula: x = -5-/+ the square root of 7
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
Solve using the quadratic formula
For any quadratic ax2 + bx + c = 0 we can find x by using the quadratic formulae: the quadratic formula is... [-b +- sqrt(b2 - 4(a)(c)) ] / 2a
Using the quadratic equation formula:- x = -4.706950048 and x = 0.849071913
By using the quadratic equation formula: (4x+1)(x-3) = 0
X= (3/5 , -2)
Using the quadratic equation formula: x = 1 or x = -10