A circle represented by an equation x^2 + y^2 = r^2 or a circular object represented by an equation Ax^2 + By^2 = r^2 has 2 y-intercepts and 2 x-intercepts.
Yes. A quadratic function can have 0, 1, or 2 x-intercepts, and 0, 1, or 2 y-intercepts.
(4x)(2y) would be factored as such: 4x = 2 • 2 • x 2y = 2 • y 2(2x)(y)
If 2 equations are perpendicular to one another they can have different y-intercepts, depending on how they are situated on a (x,y) graph.
y=xsquared-4x+2
The x intercept is 0.5 and the y intercept is -2.
-4x + y = 8At the x-intercept, 'y' is zero.-4x = 8-x = 2x = -2At the y-intercept, 'x' is zero.y = 8
4x + 3y = 6y 4x = 3y 4/3 x = y The slope is 4/3 and the y intercept is 0.
x=3 y=2 z=6
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If you mean: 4x+5y=-20 then the y intercept is (0, -4) and x intercept is (-5, 0)
factors are (4x + 1)(3x - 2) so y = 0 when x = minus a quarter and x = two-thirds
Find the two X intercepts. Set = to 0 4X + 3 = 0 X = -3/4 ( while Y = 3) 4X - 2 = 0 X = 1/2 ( while Y = -2) Now you have two points for each parallel line and can draw the graph
y intercept: x = 0 3y = 0 y = 0 x intercept: y=0 -4x = 0 x = 0 (0,0)
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A circle represented by an equation x^2 + y^2 = r^2 or a circular object represented by an equation Ax^2 + By^2 = r^2 has 2 y-intercepts and 2 x-intercepts.