0
What else can I help you with?
What are the solutions for X squared minus 5x equals 6?
The solutions to the quadratic equation are: x = -1 and x = 6
X 2 5x -6 What are the solutions to the quadratic equation?
x2+5x-6 = 0 (x+6)(x-1) = 0 x = -6 or x = 1
What is the most simplest way of solving quadratic equations?
Use the quadratic formula. A calculator will help with the squares and fractions and especially with square roots. If the equation is ax2 +bx +c = 0, then x = (-b +/- sqrt(b2-4ac))/2a. With a simple equation like x2+5x-6=0, you can solve by factoring: (x+6)(x-1)=0 <=> x=-6 or x=1. However, the quadratic formula will work on any equation.
What are at least four ways in how to solve a quadratic equation?
1 By factorizing it 2 By sketching it on the Cartesian plane 3 By finding the difference of two squares 4 By completing the square 5 By using the quadratic equation formula 6 By finding its discriminant to see if it has any solutions at all
Solve y 3x2 6x-9 using the quadratic formula?
To find the zeros of this quadratic function, y= 3x^2 + 6x - 9, we must equal y to 0. So we have the quadratic equation: 3x^2+6x-9 = 0, where a = 3, b = 6, and c = -9 The quadratic formula: x = [-b ± √(b^2 - 4ac)]/(2a) substitute what you know into this formula; x = [-6 ± √(6^2 - 4 x 3 x -9)]/(2 x 3) x = [-6 ± √(36 +108)]/6 x = (-6 ± √144)/6 x = (-6 ± 12)/6 Simplify: mulyiply by 1/6 both the numerator and the denominator; x = -1 ± 2 x = -1 + 2 or x = -1 - 2 x = 1 or x = -3 So solutions are -3 and 1. If you check the answers by plugging them into the equation, you will see that they work.
What are the solutions for X squared minus 5x equals 6?
The solutions to the quadratic equation are: x = -1 and x = 6
How many real solution exist for the equation 1.1x2 plus 3.3x plus 4 equals 6?
1.1x2 + 3.3x + 4 = 6 First rearrange the equation to equal zero so that we can use the quadratic formula. 1.1x2 + 3.3x - 2 = 0 Using the quadratic formula, the solutions are x = -3.52 and x = 0.52 Both of these solutions are real, so the original equation has two real solutions.
What type of equation is b2-4ac?
6
X 2 5x -6 What are the solutions to the quadratic equation?
x2+5x-6 = 0 (x+6)(x-1) = 0 x = -6 or x = 1
What is -1x plus 5x plus 6?
-x^2 - 11x - 30 If you intended -1(x squared), making a quadratic equation, the solutions are -1 and +6.
What is a quadratic equation in vertex form for a parabola with vertex (11 -6)?
A quadratic equation in vertex form is expressed as ( y = a(x - h)^2 + k ), where ((h, k)) is the vertex of the parabola. For a parabola with vertex at ((11, -6)), the equation becomes ( y = a(x - 11)^2 - 6 ). The value of (a) determines the direction and width of the parabola. Without additional information about the parabola's shape, (a) can be any non-zero constant.
2x2 equals 10x plus 6?
46Improved answer:First rearrange this quadratic equation which will have two solutions :2x2-10x-6 = 0Simplify the equation by dividing all terms by 2:x2-5x-3 = 0Then by using the quadratic equation formula it will work out as:x = (5 + the square root of 37)/2or x = (5 - the square root of 37)/2
What represents the solutions of a quadratic equation?
A quadratic equation is one that can be written as y=Ax^2+Bx+C. The solutions are the values of x that make y=0. If an equation has solutions, say x=M and x=N, then Ax^2+Bx+C=(x-M)(x-N). For example: y=x^2-5x+6 So we want to find what values of x make the equation true: 0=x^2-5x+6 This happens at x=2, when y=(2)^2-5*(2)+6 =4-10+6 =0 and at x=3, when y=(3)^2-5*(3)+6 =9-15+6 =0 So the solutions are x=2 and x=3, and the equation can be written as y=(x-2)(x-3).
What is the radical equation 4 equals x2-2-x?
It is a quadratic equation and can be rearranged in the form of:- x2-x-6 = 0 (x+2)(x-3) = 0 Solutions: x = -2 and x = 3
What is An equation with one variable that has an exponent of 2?
An example of an equation with one variable that has an exponent of 2 is ( x^2 - 5x + 6 = 0 ). This quadratic equation can be factored into ( (x - 2)(x - 3) = 0 ), giving the solutions ( x = 2 ) and ( x = 3 ). Quadratic equations like this one typically represent parabolic graphs.
How do you Find the equation of a quadratic function with solutions of -2 and ¾?
If: x = -2 and x = 3/4 Then: (4x-3)(x+2) = 0 So: 4x2+5x-6 = 0
What is the discriminant of this equation 8x2 5x 6 0?
To find the discriminant of the quadratic equation (8x^2 + 5x + 6 = 0), we use the formula (D = b^2 - 4ac), where (a = 8), (b = 5), and (c = 6). Substituting these values gives us (D = 5^2 - 4(8)(6) = 25 - 192 = -167). Since the discriminant is negative, this indicates that the equation has no real solutions and two complex solutions.
