(x+11)(x-6)
x^2 + 5x - 66 = 0
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The solutions to the quadratic equation are: x = -1 and x = 6
x2+5x-6 = 0 (x+6)(x-1) = 0 x = -6 or x = 1
Use the quadratic formula. A calculator will help with the squares and fractions and especially with square roots. If the equation is ax2 +bx +c = 0, then x = (-b +/- sqrt(b2-4ac))/2a. With a simple equation like x2+5x-6=0, you can solve by factoring: (x+6)(x-1)=0 <=> x=-6 or x=1. However, the quadratic formula will work on any equation.
1 By factorizing it 2 By sketching it on the Cartesian plane 3 By finding the difference of two squares 4 By completing the square 5 By using the quadratic equation formula 6 By finding its discriminant to see if it has any solutions at all
To find the zeros of this quadratic function, y= 3x^2 + 6x - 9, we must equal y to 0. So we have the quadratic equation: 3x^2+6x-9 = 0, where a = 3, b = 6, and c = -9 The quadratic formula: x = [-b ± √(b^2 - 4ac)]/(2a) substitute what you know into this formula; x = [-6 ± √(6^2 - 4 x 3 x -9)]/(2 x 3) x = [-6 ± √(36 +108)]/6 x = (-6 ± √144)/6 x = (-6 ± 12)/6 Simplify: mulyiply by 1/6 both the numerator and the denominator; x = -1 ± 2 x = -1 + 2 or x = -1 - 2 x = 1 or x = -3 So solutions are -3 and 1. If you check the answers by plugging them into the equation, you will see that they work.