If: 3x -5y = 16 then y = 0.6x -3.2
If: xy = 7 then x(0.6x -3.2) -7 = 0
Removing brackets: 0.6x^2 -3.2x -7 = 0
Dividing all terms by 0.6: x^2 -16/3x -35/3 = 0
Completing the square: (x -8/3)^2 -64/9 -35/3 = 0 => (x -8/3)^2 = 169/9
Square root both sides: x -8/3 = -13/3 or +13/3
Add 8/3 to both sides: x = -5/3 or x = 7
Solutions by substitution are: x = -5/3, y = -21/5 and x = 7, y = 1
They are simultaneous equations and their solutions are x = 41 and y = -58
They are: (3, 1) and (-11/5, -8/5)
The solutions are: x = 4, y = 2 and x = -4, y = -2
Simultaneous equations.
The system is simultaneous linear equations
Through a process of elimination and substitution the solutions are s = 8 and x = 5
They are simultaneous equations and their solutions are x = 41 and y = -58
They are: (3, 1) and (-11/5, -8/5)
The solutions are: x = 4, y = 2 and x = -4, y = -2
Simultaneous suggests at least two equations.
Do you mean: 4x+7y = 47 and 5x-4y = -5 Then the solutions to the simultaneous equations are: x = 3 and y = 5
If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
Simultaneous equations.
The system is simultaneous linear equations
I notice that the ratio of the y-coefficient to the x-coefficient is the same in both equations. I think that's enough to tell me that their graphs are parallel. So they don't intersect, and viewed as a pair of simultaneous equations, they have no solution.
The solutions work out as: x = 52/11, y = 101/11 and x = -2, y = -11
x = -3 y = -2