It is the input value to the function called "f(x)"
If f(x)= x + 1, an input value of 2 ( x equals 2) would give us 2 + 1, or 3.
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The expression fxfxf means f(f(x)f(x)), where f(x) is a function of x. This is not equivalent to f cubed (f^3(x)), which would mean f(f(f(x))). In fxfxf, the function f(x) is applied twice to the input x, whereas in f cubed, the function is applied three times. The two expressions are different due to the number of times the function is applied to the input.
Let f(x)=abs(x) , absolute value of x defined on the interval [5,5] f(x)= |x| , -5 ≤ x ≤ 5 Then, f(x) is continuous on [-5,5], but not differentiable at x=0 (that is not differentiable on (-5,5)). Therefore, the Mean Value Theorem does not hold.
Even polynomial functions have f(x) = f(-x). For example, if f(x) = x^2, then f(-x) = (-x)^2 which is x^2. therefore it is even. Odd polynomial functions occur when f(x)= -f(x). For example, f(x) = x^3 + x f(-x) = (-x)^3 + (-x) f(-x) = -x^3 - x f(-x) = -(x^3 + x) Therefore, f(-x) = -f(x) It is odd
You would have been given a function for f(x) and another function for g(x). When you want to find f(g(x)), you put the function for g(x) wherever x occurs in f(x). Example: f(x)=3x+2 g(x)=x^2 f(g(x))=3(x^2)+2 I'm not sure what you mean by address domain and range. They depend on what functions you're given.
You must provide a complete equation for the function. Do you mean f(x) = 1.5x + 7.6 or something else?