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What are the zeros of the polynomial function f(x) x(x plus 5)(x and ndash 8)?
They are x = 0, -5 and +8.
What are the zeros for this function?
The function is F(x)= x^3+3x^2-6x+20
If f(x)2x-1 and g(x) x plus 2 fimd (f plus g)(x)?
h(x)=3x-4
For f x 2x plus 1 and g x x2-7 find f g x?
f(x) = 2x + 1 g(x) = x^2 - 7 So f*g(x) = f(g(x)) = f(x^2 - 7) = 2*(x^2 - 7) + 1 = 2*x^2 - 14 + 1 = 2*x^2 - 13
What are the zeros of the function f(x) -4(x-3)(x 5)?
what is the sum of
What are the zeros if f of x equals x root 2 plus 4x plus 8?
To find the zeros of the function ( f(x) = x\sqrt{2} + 4x + 8 ), we set the equation equal to zero: ( x\sqrt{2} + 4x + 8 = 0 ). This can be rewritten as ( x(\sqrt{2} + 4) + 8 = 0 ). Solving for ( x ), we get ( x(\sqrt{2} + 4) = -8 ), leading to ( x = \frac{-8}{\sqrt{2} + 4} ). Thus, the zeros of the function are ( x = \frac{-8}{\sqrt{2} + 4} ).
State whether the following is a polynomial function give the zero s of the function if the exist f x x 2-6x plus 8?
The function ( f(x) = x^2 - 6x + 8 ) is a polynomial function because it is a quadratic expression. To find the zeros, we can factor it as ( (x - 2)(x - 4) ), which gives us the zeros ( x = 2 ) and ( x = 4 ). Thus, the zeros of the function are 2 and 4.
What are the zeros of the function f of x equals 5x cubed minus x squared minus 18x plus 8?
-2, 1.74 and 0.46
X2 plus 11x plus 6 rational zeros?
x^2 + 11x + 6 has no rational zeros.
What are the zeros of the polynomial function f(x)x3-2x2-8x?
To find the zeros of the polynomial function ( f(x) = x^3 - 2x^2 - 8x ), we first factor the expression. We can factor out ( x ) from the polynomial, giving us ( f(x) = x(x^2 - 2x - 8) ). Next, we can factor the quadratic ( x^2 - 2x - 8 ) into ( (x - 4)(x + 2) ), leading to ( f(x) = x(x - 4)(x + 2) ). Therefore, the zeros of the function are ( x = 0 ), ( x = 4 ), and ( x = -2 ).
What are the zeros of the polynomial function f(x) x(x plus 5)(x and ndash 8)?
They are x = 0, -5 and +8.
Real zeros of x3 -13x plus 18?
f(2) = 8 - 26 + 18 = 0 (x-2) is a factor of f(x), x = 2 f(x) = (x-2)(x2 + 2x -9) x2 + 2x - 9 = 0 (x+1)2 - 10 = 0 x + 1 = +-sqrt10 x = -1 + sqrt10, -1 - sqrt10, 2
How you Find the quadratic polynomial whose zeros are 2 and -3?
To find the quadratic polynomial whose zeros are 2 and -3, we can use the fact that a polynomial can be expressed in factored form as ( f(x) = a(x - r_1)(x - r_2) ), where ( r_1 ) and ( r_2 ) are the zeros. Here, substituting ( r_1 = 2 ) and ( r_2 = -3 ), we have ( f(x) = a(x - 2)(x + 3) ). Expanding this, we get ( f(x) = a(x^2 + x - 6) ). For simplicity, we can choose ( a = 1 ), giving us the polynomial ( f(x) = x^2 + x - 6 ).
Is it always true that between any two zeros of the derivative of any polynomial there is a zero of the polynomial?
No. Consider the polynomial: f(x) = x3 + 4x2 + 4x + 16 then f'(x) = 3x2 + 8x + 4 = (3x + 2)(x + 2) => x = -2/3, -2 are the zeros of f'(x) Using the second derivative: f''(x) = 6x + 8 it can be seen that: f''(-2) = -4 -> x = -2 is a maximum f''(-2/3) = +4 -> x = -2/3 is a minimum But plugging back into the original polynomial: f(-2) = 16 f(-2/3) = 14 22/27 Between the zeros of the first derivative, the slope of the polynomial is negative so that the polynomial is always decreasing in value, but as the polynomial is greater than zero at the zeros of the first derivative, it cannot become zero between them. That is it has no zeros between the zeros of its first derivative f(x) = x3 + 4x2 + 4x + 16 = (x + 4)(x2 + 4) has only 1 zero at x = -4.
Can you determine the zeros of f x squared 64 by using a graph?
Yes, you can determine the zeros of the function ( f(x) = x^2 - 64 ) using a graph. The zeros correspond to the x-values where the graph intersects the x-axis. By plotting the function, you can see that it crosses the x-axis at ( x = 8 ) and ( x = -8 ), which are the zeros of the function.
What are the zeros for this function?
The function is F(x)= x^3+3x^2-6x+20
What is the domain of the function f x x 2 plus 4?
The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
