(2y)3 = 8y3
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4x-2y+3x+2y When simplified: 7x
22
3xy-2y=0 3xy=2y y=2y (3x) y/2y=3x 1/2=3x multiply across by 2 1=6x 1/6=x therefore substituting x=1/6 into 3xy-2y; 3(1/6)y-2y=0 1/2y=2y y=2y/0.5 0.5 aka 1/2 y=1
6x-2x-6xy-2x-2y4x-2y=2x-2y-14xy
(3x-2y)2=