4x-2y+3x+2y When simplified: 7x
22
3xy-2y=0 3xy=2y y=2y (3x) y/2y=3x 1/2=3x multiply across by 2 1=6x 1/6=x therefore substituting x=1/6 into 3xy-2y; 3(1/6)y-2y=0 1/2y=2y y=2y/0.5 0.5 aka 1/2 y=1
6x-2x-6xy-2x-2y4x-2y=2x-2y-14xy
(3x-2y)2=
2y squared * y cubed= 2y^5 (2y to the fifth power)
9y cubed plus 2y squared
x3+8y3 = (x+2y)(x2-2xy+4y2) The discriminant of the quadratic factor is 4y2-16y2 < 0 so there are no real roots. So the only real root of the original polynomial is x+2y=0 or x = -2y
(xy - 7)(x^2y^2 + 7xy + 49)
2x^2y^3(4x^2 - 3xy + 1)
y^(3) - 2y^(2) + 4y Factor out 'y' Hence y(y^2 - 2y + 4) This will not factor any further.
-6
2y3 - 54 = 2*(y3 - 27) = 2*(y - 3)*(y2 + 3y + 9)
4x-2y+3x+2y When simplified: 7x
-2y+y = -y
3x - 2y and 3x + 2y are in their simplest form. They don't factor.
-6x = 2y - 120 -2y -2y -2y - 6x = -120 +6x +6x -2y = 6x - 120 -2y/-2 = 6x/-2 - 120/-2 y = -3x + 60