The equation for the size of an interior angle of an n-sided regular polygon is (n-2)180/n. When n=7, the interior angle of a regular sided shape would be 5x180/7 or approximately 128.57. The polygon in the question has an interior right angle (90 degree angle) and thus cannot be a regular shape. A 7 sided shape is called a heptagon. Thus, the shape described in the question is an irregular heptagon.
Sum of interior angles is (2n-4) right angles There are 66 right angles in 5940 degrees So (2n - 4) = 66 2n = 70 n = 35
Your polygon has 60 sides. Total interior angles 116 x 90 = 10440 degrees. This works because interior angles of any n-sided polygon total (2n - 4 right angles or 180n - 360 degrees
(2n - 4) right angles where n is the number of sides.
There are lots of polygons like that. If by 1 right angle, you mean exactly 1 right angle, there are no such quadrilaterals, but there are pentagons (in fact n-gons for all n>=5.)
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There is a formula which can help.The sum of the interior angles of a polygon is 2n - 4 right angles.When n = 12 then the interior angles total (2 x 12) - 4 = 24 - 4 = 20 right angles.Then for a regular polygon, each angle measures (20 x 90) / 12 = 150°.When the polygon is a regular polygon then it is perhaps quicker to calculate the external angle from which the interior angle can then be determined.Exterior angle = 360 /12 = 30°Interior angle = 180 - 30 = 150°
An irregular septagon: the right-angle will prevent it being regular.
Two methods :_ 1) The sum of the interior angles of a regular polygon is 2n - 4 right angles. For a 14 sided polygon then (2 x 14) - 4 = 24 right angles = 24 x 90 = 2160° Therefore each interior angle = 2160 ÷ 14 = 154.29° (2dp) 2) The external angle of a 14 sided regular polygon = 360 ÷ 14 = 25.71° The interior angle = 180 - external angle = 180 - 25.71 = 154.29°
The sum of the interior angles of a polygon is 2n - 4 right angles where n is the number of sides. When n = 21 then 2n - 4 = 42 - 4 = 38 right angles = 38 x 90 = 3420°. NOTE : If the polygon is a regular polygon then each interior angle measures 3420 ÷ 21 = 162.86°.
The answer to this would be any acute polygon, such as an equilateral triangle. The definition of acute polygons is that no angle in the polygon is greater than or equal to 90 degrees.
Total of interior angles of an n-sided polygon is 180n -360 or (2n -4) right angles. If the polygon is regular then each angle is the total obtained above divided by n.
Any polygon can have a right angle. A right angled triangle is an example.
Any polygon, if it is not regular, can have 1 right angle.
Oh, dude, you're really reaching for those angles, huh? Yeah, technically, there is a polygon with an interior angle sum of 9000. It's called a nonagon, or a nine-sided polygon. But like, who even needs that many angles, am I right?
No. The interior angle and exterior angle at the same vertex are supplementary. Each of them is (180 degrees minus the other). In rectangles (including squares), the interior and exterior angles at each vertex are both right angles.
A right angle triangle
The sum of the interior angles of a polygon is 2n-4 Right Angles For a nonagon (2x9)-4 RAs = 14x90°=1260° To find the interior angle of a regular nonagon, divide this by 9 which gives 140° To find the exterior angle, subtract this from 180 and you get 40°. The sum of the exterior angles of a polygon is 360°, so for a regular polygon you can also divide this by the number of sides, which in this case also gives: 360° ÷ 9 = 40°