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How do you find zeros of a polynomial?
If there is one variable. Then put each variable equal to zero and then solve for the other variable.
How do you solve this equation Form a polynomial with the given zeros 2 mult 2 3 5 I don't want the answer I want to know how to find the answer?
If you have the zeros of a polynomial, it is easy, almost trivial, to find an expression with those zeros. I am not sure I understood the question correctly, but let's assume you have the zero 2 with multiplicity 2, and other zeros at 3 and 5. Just write the expression: (x-2)(x-2)(x-3)(x-5). (Example with a negative zero: if there is a zero at "-5", the factor becomes (x- -5) = (x + 5).) You can multiply this out to get the polynomial if you like. For example, if you multiply every term in the first factor with every term in the second factor, you get x2 -2x -2x + 4 = x2 -4x + 4. Next, multiply each term of this polynomial with each term of the next factor, etc.
How do you use the discriminant to find the number and type of zeros of a function?
If the discriminant is positive, then the function has two real zeros. If it is zero, then the function has one real zero. If it is negative, then it has two complex conjugate zeros.This assumes that we are talking about a standard second order polynomial equation, i.e. quadratic equation, in the form Ax2 + Bx + C = 0, and that the discriminant is B2 - 4AC, which is a part of the standard solution of these kind of equations.
How do you find the zeros?
Solve the equation - by whatever means available to you: factorising, graphical, numerical approximations, etc.
A condition that must be met before you can use the quadratic formula to find the solutions?
The equation must be written such that the right side is equal to zero. And the resulting equation must be a polynomial of degree 2.
How do you find polynomial whose zeros are given?
when the equation is equal to zero. . .:)
How do you find the zeros of any given polynomial function?
by synthetic division and quadratic equation
what are all of the zeros of this polynomial function f(a)=a^4-81?
Find All Possible Roots/Zeros Using the Rational Roots Test f(x)=x^4-81 ... If a polynomial function has integer coefficients, then every rational zero will ...
How do you find zeros of a polynomial?
If there is one variable. Then put each variable equal to zero and then solve for the other variable.
In a cubic polynomial 2xxx-5xx-14x 8 find the sum of the zeros?
2x^3 - 5x^2 - 14x + 8 Let P(x) represents the cubic polynomial. We can find the sum of x-values which make P(x) = 0, (the sum of the roots of the equation) P(x) = 2x^3 - 5x^2 - 14x + 8 P(x) = 0 2x^3 - 5x^2 - 14x + 8 = 0 Since the degree of this polynomial is odd, then the sum of the roots is -[a(n - 1)/an], where a(n-1) is -5 and an is 2. So we have, -[a(n - 1)/an] = -(-5/2) = 5/2 Thus the sum of the roots is 5/2.
How Find a polynomial degree of 3 whose zeros are -2 -1 and 5?
Multiply x3 - 2x2 - 13x - 10
How do you solve this equation Form a polynomial with the given zeros 2 mult 2 3 5 I don't want the answer I want to know how to find the answer?
If you have the zeros of a polynomial, it is easy, almost trivial, to find an expression with those zeros. I am not sure I understood the question correctly, but let's assume you have the zero 2 with multiplicity 2, and other zeros at 3 and 5. Just write the expression: (x-2)(x-2)(x-3)(x-5). (Example with a negative zero: if there is a zero at "-5", the factor becomes (x- -5) = (x + 5).) You can multiply this out to get the polynomial if you like. For example, if you multiply every term in the first factor with every term in the second factor, you get x2 -2x -2x + 4 = x2 -4x + 4. Next, multiply each term of this polynomial with each term of the next factor, etc.
How do you find the real zeros of a cubic function without a calculator?
In general, there is no simple method.
How do you use the discriminant to find the number and type of zeros of a function?
If the discriminant is positive, then the function has two real zeros. If it is zero, then the function has one real zero. If it is negative, then it has two complex conjugate zeros.This assumes that we are talking about a standard second order polynomial equation, i.e. quadratic equation, in the form Ax2 + Bx + C = 0, and that the discriminant is B2 - 4AC, which is a part of the standard solution of these kind of equations.
What statement must be true of an equation before you can use the quadratic formula to find the solutions?
The quadratic formula can be used to find the solutions of a quadratic equation - not a linear or cubic, or non-polynomial equation. The quadratic formula will always provide the solutions to a quadratic equation - whether the solutions are rational, real or complex numbers.
How do you find the zeros in an equation by looking on a graph?
They are all the points where the graph crosses (or touches) the x-axis.
How do you find the zeros?
Solve the equation - by whatever means available to you: factorising, graphical, numerical approximations, etc.
