In algebra, the expression "b plus 14" can be simplified by combining the variable 'b' with the constant 14. This results in the sum of the two values. So, "b plus 14" simplifies to "b + 14". It is important to note that without specific values assigned to 'b', the expression cannot be further simplified or evaluated.
b times b times b = b3 b plus b plus b = 3b
It is: B+2b when simplified assuming B and b have different values
7a-2b
(x - a) + (x - a) + (b) = 2 (x - a) + (b) = x - a + x - a + b = 2x - 2a + b
It is a*a + b*b + c*c
It is an algebraic expression in the form of: b+14
There is no such word as "abrical".The algebraic expression for b plus 14 is b + 14
It is: b = -3
b + 14. There is nothing further than can be done without additional information about b.
1-6b+7=14 8-6b =14 -6b =6 -b =1 b =-1
y = x2 + 14x + 21 a = 1, b = 14 x = -b/2a = -14/2*1 = -7
A=8 B=4 C=14 Yes, I know I'm a genius. Mak - the all knowing one. MWAHAHAH!
b = 14
12
y = x2 + 14x + 21; a = 1, b = 14, c = 21 x-coordinate = -b/2a = -14/2 = -7 if it is y = x2 + 14 + 21, the x-coordinate is zero, since b = 0.
14*13=182
a+b = 17a+c = 36 ----> c = 36 - ab+c = 25 ----> c = 25 - bSo since both are c, we say36 - a = 25 -bFrom this : 11 = a - bLook at 1st eqn: a + b = 17Now we have: a - b = 11 ----> a = 11 + bSo we can substitute that into a + b = 17 to make:(11 + b) + b = 1711 + 2b = 17So b = 3If b = 3, then a + 3 = 17 , so a = 14, 3 + c = 25, so c = 22So a=14, b=3, c=22, so a+b+c = 14+3+22 = 39