Apparently that can't be solved with a finite number of so-called "elementary functions". You can get the beginning of the series expansion here:
http://www.wolframalpha.com/input/?i=integrate+x^x
-cos x + C
S 2/x d/x bring the constant 2 out in front of the sign of integration 2 S 1/x dx you should know the integration of 1/x 2*ln(x) + C
When you with respect to the x-axis then this is like saying with reference to the x-axis. You are using the x-axis as a guide.
int cos3x=sin3x/3+c
The number (before integration) would be written out as simply x^(3/2). The power rule tells us that derivative of x^n=n*x^(n-1). To integrate, just try doing this backwards. The exponent would have to be 5/2, but the derivative of x^(5/2) is 5/2*x^(3/2). To fix this problem, just multiply the number 2/5, reducing the coefficient of your number before integration one as it should be. S(x*√x)=2/5*x^(5/2)+c
∫ ex dx = ex + CC is the constant of integration.
∫ ax dx = ax/ln(a) + C C is the constant of integration.
Assuming integration is with respect to a variable, x, the answer is 34x + c where c is the constant of integration.
The indefinite integral of x dt is xt
∫ xn dx = xn+1/(n+1) + C (n ≠-1) C is the constant of integration.
∫ f(x)nf'(x) dx = f(x)n + 1/(n + 1) + C n ≠-1 C is the constant of integration.
∫ d/dx f(x) dx = f(x) + C C is the constant of integration.
∫ sin(x) dx = -cos(x) + CC is the constant of integration.
∫ cos(x) dx = sin(x) + CC is the constant of integration.
∫ cot(x) dx = ln(sin(x)) + CC is the constant of integration.
∫ f'(x)/f(x) dx = ln(f(x)) + C C is the constant of integration.
∫ f'(x)(af(x) + b)n dx = (af(x) + b)n + 1/[a(n + 1)] + C C is the constant of integration.