4x2 + 3x - 6 is a quadratic polynomial. Any polynomial determine a polynomial function.
Thus, f(x) = 4x2 + 3x - 6, which graph is a parabola that opens upward (4 > 0).
For any value of x, we can find a corresponding value of y.
If x = 0, then y = -6; (0, -6) the y-intercept point, which tells us that the parabola cuts the x-axis.
Let's find the values of x (the x-intercepts), which make f(x) = 0.
0 = 4x2 + 3x - 6 factor it since 4(-6) = -24 = 8(-3) and 8 - 3 = 5
0 = [(4x + 8)/4](4x - 3)
0 = (x + 2)(4x - 3) let each factor equal to zero
(x + 2) = 0 or (4x - 3) = 0 solve for x
x = -2 or x = 3/4 the x-intercepts
The axis of symmetry, x = -b/2a = -3/2*4 = -3/8. Thus, (0, -6) is symmetrical to (2*-3/8, -6) = (-3/4, -6).
Since the vertex lies on the axis of symmetry, the vertex is [-3/8, f(-3/8)].
f(-3/8) = 4(-3/8)2 + 3(-3/8) - 6 = 9/16 - 9/8 - 6 = (9 - 18 - 96)/8 = -105/8 = -(13 and 1/8) .
Thus, the vertex is (-3/8, -105/8).
Just plot the points and draw the parabola that passes through them.
4x2 + 3x - 6 is a second degree polynomial. Since the polynomial function f(x) = 4x2 + 3x - 6 has 2 zeros, it has 2 linear factors. Since we cannot factor the given polynomial, let's find the two roots of the equation 4x2 + 3x - 6 = 0, which are the zeros of the function. 4x2 + 3x - 6 = 0 x2 + (3/4)x = 6/4 x2 + (3/4)x + (3/8)2 = 6/4 + 9/64 (x + 3/8)2 = 105/64 x + 3/8 = ± √(105/64) x = (-3 ± √105)/8 x = -(3 - √105)/8 or x = -(3 + √105)/8 Thus, the linear factorization of f(x) = 4[x + (3 - √105)/8][x + (3 + √105)/8].
4x2 - 2x - 12= 2x2 - x - 6= 2x2 - 4x + 3x - 6= 2x(x - 2) + 3(x - 2)= (x - 2)(2x + 3)
The expression x2 + 3x +8 is a quadratic trinomial.
If the missing signs are all pluses, that's 4x2 + 3x + 3
(x + 5)(x - 2)x2 + 3x - 10this is your quadratic equation
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
Quadratic equation formula
The given quadratic expression can not be factorized because its discriminant is less than zero.
No integer roots. Quadratic formula gives 1.55 and -0.81 to the nearest hundredth.
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
3(4x2 - x + 2)
y=4x2+3x+8
4x2 - 3x - 9
No. [ y = 4x2 ] is a quadratic equation.
4x2 - 6x - 12 = 2 (2x2 - 3x - 6) There are no integer roots, the approximate roots are 2.64 and -1.14
4x2 + 3x - 6 is a second degree polynomial. Since the polynomial function f(x) = 4x2 + 3x - 6 has 2 zeros, it has 2 linear factors. Since we cannot factor the given polynomial, let's find the two roots of the equation 4x2 + 3x - 6 = 0, which are the zeros of the function. 4x2 + 3x - 6 = 0 x2 + (3/4)x = 6/4 x2 + (3/4)x + (3/8)2 = 6/4 + 9/64 (x + 3/8)2 = 105/64 x + 3/8 = ± √(105/64) x = (-3 ± √105)/8 x = -(3 - √105)/8 or x = -(3 + √105)/8 Thus, the linear factorization of f(x) = 4[x + (3 - √105)/8][x + (3 + √105)/8].