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What is Length and width of a rectangular lot with a perimeter of 88 meters if the length is 4 meters more than the width?
P = 2(l + w) & l = w + 4 Substitute P = 2((w + 4) + w) P = 2(2w + 4) P = 4w + 8 4w = P - 8 w = (P - 8) / 4 Substitute w = (88 - 8) / 4 w = 80/4 w = 20 m Hence l = 24 m
What is the length of a rectangle that has a perimeter of 36 cm and a width of 8 cm?
perimeter = 2*width + 2*length 36= 2*8 +2*length2*length=36-162*length=20length = 10 cm
What is the answer to this math problem The area of a rectangular computer screen is 4x2 plus 20x plus 16 The width of the screen is 2x plus 8 What is the length of the screen?
Area = 4x2 + 20x + 16 Width = 2x + 8 Length = ? To begin, we will factorise all the expressions Area = 4(x2 + 5x + 4) = 4(x+1)(x+4) Width = 2(x+4) Length = ? The formula for Area is given by: Area = Length . Width (A dot has been used to represent multiplication in the above formula so as not to confuse it with the variable x) Substituting in our expressions for Area and Width gives: 4(x+1)(x+4) = Length . 2(x+4) Dividing both sides by 2(x+4) to solve for Length gives an answer of: Length = 2(x+1) If you look at the width and the length expressions, the width is longer than the length (which shouldn't be possible). It is most likely a mistake in the question.
How do you draw a rectangle with a perimeter of 12 units and an area equalling 8?
The rectangle would have a width of 2 and a length of 4.
A room on a floor plan has a length of 5 centimeters and a width of 8 centimeters. If the actual length of the room is 15 feet which proportion can be used to find the actual width of the room?
1 cm means 3 feet and so 8 times 3 = 24 feet
