Endpoints: A (-2, -4) and B (-8, 4)
Length of AB: 10 units
End points: (-2, -4) and (-8, 4) Length of line AB: 10
Length AB is 17 units
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
|AB| = sqrt[(5 - 2)2 + (7 - 4)2] =sqrt[9 + 9] = 3*sqrt(2)
4 units
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
End points: (-2, -4) and (-8, 4) Length of line AB: 10
Length AB is 17 units
Using the distance formula the length of ab is 5 units
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
we can create a graph with the x-axis representing the horizontal values and the y-axis representing the vertical values. let's determine whether the line segments AB and CD are congruent. The length of line segment AB can be calculated using the distance formula: AB = sqrt((x2 - x1)^2 + (y2 - y1)^2) For AB(0, 1) and CD(4, 1), the length of AB is: AB = sqrt((4 - 0)^2 + (1 - 1)^2) = sqrt(16 + 0) = sqrt(16) = 4 For CD(1, 2) and CD(1, 6), the length of CD is: CD = sqrt((1 - 1)^2 + (6 - 2)^2) = sqrt(0 + 16) = sqrt(16) = 4 Since the length of AB is equal to the length of CD (both are 4 units), we can conclude that line segments AB and CD are congruent.
|AB| = sqrt[(5 - 2)2 + (7 - 4)2] =sqrt[9 + 9] = 3*sqrt(2)
12
4 units
(x+3)2 + (y+4)2 = 4
You need to provide more information in order to answer this question. However, you need to use either Subsitution or Elimination. Substitue the equation of Line AB into the equation of Line CD. E.g. Line AB y=2x Line CD y=3x+2 2x=3x+2 3x-2x=-2 x=-2 Sub x=-2 into either equation y=2(-2) y=-4 Therefore, the point of intersection is (-2, -4).