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The length is 3*sqrt(5) = 6.7082, approx.
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What is the length of a right triangle if the base is 8 and hypotenuse is 10?
Use the Pythagorean theorem. a^2 + b^2 = c^2 a = base b = length c = hypotenuse 8^2 + b^2 = 10^2 b^2 = 10^2 - 8^2 b = sqrt(10^2 - 8^2) b = sqrt(100 - 64) b = sqrt(36 b = 6 ------------------the length
If A (00) and B (8 .2) what is the length of ab?
To find the length of the line segment AB between the points A(0, 0) and B(8, 2), you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Substituting the coordinates, we have ( d = \sqrt{(8 - 0)^2 + (2 - 0)^2} = \sqrt{64 + 4} = \sqrt{68} ). Therefore, the length of AB is ( \sqrt{68} ), which simplifies to ( 2\sqrt{17} ).
How can you express in radical form the length of the diagonal of a square whose sides are each 2?
Let 'a' and 'b' be the length of one side and diagonal of a square. Pythagorus's theorem as applied to a square: a^2 + a^2 = b^2. Substituting a = 2 into the equation, we have b^2 = 2^2 + 2^2 = 8. b = sqrt(8) = 2 * sqrt(2). Q.E.D. ===========================
What is the transformation of B(4 8) when dilated by a scale factor of 2 using the origin as the center of dilation?
To find the transformation of point B(4, 8) when dilated by a scale factor of 2 using the origin as the center of dilation, you multiply each coordinate by the scale factor. Thus, the new coordinates will be B'(4 * 2, 8 * 2), which simplifies to B'(8, 16). Therefore, point B(4, 8) transforms to B'(8, 16) after the dilation.
Can you solve for b in the equation 12 equals negative 4 over 2 time negative 2 plus b?
12 = -4/2 * -2 + b 12 = -2 * -2 + b 12 = 4 + b 8 = b
If A is the point -2 -4 and B is -8 4 what is the length of AB?
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
If A (-2 -4) and B (-8 4) what is the length of line AB?
End points: (-2, -4) and (-8, 4) Length of line AB: 10
If A is the point -2 -4 and B is the point -8 4 what is the length of AB?
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
If A (-2 -4) and B (-8 4) what is the length of Ab?
Using the distance formula the length of ab is 5 units
If A 0 0 and B 8 2 what is the length of ?
(0,8)2 + (0,2)2 8(2=69 2(2=4 69+4=74√
What is the length of the longest side of a triangle that has vertices at 4 -2 -4 -2 and 4 4?
a=8 b=6 c=10 answer is 10
What is the length of a right triangle if the base is 8 and hypotenuse is 10?
Use the Pythagorean theorem. a^2 + b^2 = c^2 a = base b = length c = hypotenuse 8^2 + b^2 = 10^2 b^2 = 10^2 - 8^2 b = sqrt(10^2 - 8^2) b = sqrt(100 - 64) b = sqrt(36 b = 6 ------------------the length
If A(-2-4) and B(-8-4) what is the length of AB?
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
If a (0 0) and b (8 2) what is the length of ab?
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
If A (00) and B (8 .2) what is the length of ab?
To find the length of the line segment AB between the points A(0, 0) and B(8, 2), you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Substituting the coordinates, we have ( d = \sqrt{(8 - 0)^2 + (2 - 0)^2} = \sqrt{64 + 4} = \sqrt{68} ). Therefore, the length of AB is ( \sqrt{68} ), which simplifies to ( 2\sqrt{17} ).
How can you express in radical form the length of the diagonal of a square whose sides are each 2?
Let 'a' and 'b' be the length of one side and diagonal of a square. Pythagorus's theorem as applied to a square: a^2 + a^2 = b^2. Substituting a = 2 into the equation, we have b^2 = 2^2 + 2^2 = 8. b = sqrt(8) = 2 * sqrt(2). Q.E.D. ===========================
If A squared plus B squared equals C squared and C equals 8 and A and B are the same length what are A and B?
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