The answer is 6. The formula is 1/2 of base times perpendicular height. In the case of a 3:4:5 triangle, there is a right angle between the two shorter sides so they are inherently perpendicluar to each other. So you can either say the base is 3 and the perpendicular height is 4 or the base is 4 and the perpendicular is 3 - either way 1/2 x 3 x 4 = 6. Brian DOWNIE The answer is 6. The formula is 1/2 of base times perpendicular height. In the case of a 3:4:5 triangle, there is a right angle between the two shorter sides so they are inherently perpendicluar to each other. So you can either say the base is 3 and the perpendicular height is 4 or the base is 4 and the perpendicular is 3 - either way 1/2 x 3 x 4 = 6. Brian DOWNIE
Area of Equilateral Triangle A= S2 * (Root 3)/4, where A= Area of the triangle S= Side of the triangle.
no.
Area of a triangle is 1/2*Base*Height. I believe you can take it from here.
Yes, it is possible to build a triangle with side lengths of 3 cm, 4 cm, and 5 cm. This triangle would be a right triangle, following the Pythagorean theorem which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In this case, 3^2 + 4^2 = 5^2 (9 + 16 = 25), satisfying the condition for a right triangle.
Area of a triangle = 1/2 x (base) x (height) In this situation, the base [b] = height [h] + 10 And the Area = 28 So the 28 = 1/2 x (h + 10) x h The base is 14 cm and the height is 4 cm
The minimum perimeter is when the triangle is an equilateral triangle. The perimeter of any other triangle with the same area will be longer. In the case of an equilateral triangle area = (√3)/4 × side² → side = √(4×6.5 cm²/√3) → perimeter = 3 × side = 3 × √(4×6.5 cm²/√3) ≈ 11.62 cm → The triangle has a perimeter greater than or equal to approx 11.62 cm.
2 6CM
The area of triangle is : 16.0
To find the area of an equilateral triangle, you can use the formula: area = (sqrt(3)/4) * s^2 where s is the length of one side of the triangle. If the length of one side of the triangle is 6 cm, the area of the triangle is: area = (sqrt(3)/4) * 6^2 = (sqrt(3)/4) * 36 = (3.46/4) * 36 = 13.83 * 36 = 498.68 Rounded to one decimal place, the area of the triangle is approximately 499 cm^2.
Its area is 0.5*36*48 = 864 square cm and it is a right angle triangle
The area of a right triangle that has legs 7 cm and 4 cm long can be calculated using the fact that a right triangle is half of a rectangle. The area of a rectangle is l*h, so the area of a right triangle is l*h/2. In this case, the area is 14 cm^2.
This is a right angle triangle.
60 because there are 3 sides in a triangle and 60 x 3 =180, triangles are always equal to 180 * * * * * The above "answer" has nothing to do with the question! The area of an equilateral triangle with sides of s cm is s*sqrt(3)/4 square cm.
yes. take an obtuse triangle that has a base of 8cm and a height of 3cm. then, take a right triangle that has a base of 3 cm and a height of 4 cm. do the math. the obtuse triangle will have a greater area. hope this helps.
1/2*4*3 = 6 square cm
The perimeter of the equilateral triangle is 3 times 4 = 12 cm
Area of Triangle = 1/2 base x height 28 = 4 x height height = 7 cms