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What is the area of the rectangle if the base is 2x and the height is 3x?
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∙ 15y ago
6X squared
Wiki User
∙ 15y ago
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What is the area of the rectangle if the base is x plus 1 and the altitude y-2 is?
-1
The length of a rectangle is 1 more than twice its width and the area of the rectangle is 45 what are the dimensions of the rectangle?
Assign the rectangle a width 'x'. From the data in the problem the height is then '2x+1'. Multiplying the two together gives the area of the rectangle, which we know to be 45. In equation for this is: x(2x+1) = 45 or 2x^2 + x = 45. The roots of this equation can then be found either through the quadratic equation or a calculator solver (I used the solver because I'm lazy) and the answers are x = -5 and x= 4.5. The rectangle has a width of 4.5 and a height of 10.
If you double the side lengths of a rectangle why is the area of the new rectangle not twice as big as the original?
Look at it this way, suppose x is one side of the rectangle and y is the other. Then the area of the rectangle would be xy. Now if you double each side of the originial rectangle you would have each side as 2x and 2y. So the area of the new rectangle would be 2x*2y or 4xy. As you can see the new area is 4 times larger than the original.
In Calculus what is the formula for the described function A if a rectangle has area 12 m2 and the perimeter P of the rectangle is expressed as a function of the length x of one of its sides?
A=b*h area = base (times) height P=2b + 2h perimeter = 2 (times) base (plus) 2 ( times) height A= b*h 12 = b*h 12/b = h let x = b h = 12/x since x = b and h = 12/x therefore P = 2x + 2(12/x)
The length of a rectangle is five feet more than twice its width and the area of the rectangle is sixty-three Find the dimensions of the rectangle?
Let the width = X. The length is twice the width plus 5. So the length must be 2X + 5. Area = 63 ft squared = X multiplied by 2X + 5 = 2X squared + 25. 2X squared = 63 - 25 = 38 2X = square root of 38. Therefore the width is the square root of 38 divided by 2 and the length is the square root of 38 plus 5.
What is the area of the rectangle if the base is x plus 1 and the altitude y-2 is?
-1
If the base is 4x-3 and the height is 2x what is the area of the triangle?
Area of triangle is 0.5*b*h where: b = base h = height thus Area is: 0.5*(4x-3)*(2x) = (4x-3)*(x) = 4x2 - 3x
What is the formula to find the surface area of a 3D rectangle?
SA= 2x(l+w)+2x(l+h)+2x(h+w) H= Height L= Length W= Width
The length of a rectangle is 1 more than twice its width and the area of the rectangle is 45 what are the dimensions of the rectangle?
Assign the rectangle a width 'x'. From the data in the problem the height is then '2x+1'. Multiplying the two together gives the area of the rectangle, which we know to be 45. In equation for this is: x(2x+1) = 45 or 2x^2 + x = 45. The roots of this equation can then be found either through the quadratic equation or a calculator solver (I used the solver because I'm lazy) and the answers are x = -5 and x= 4.5. The rectangle has a width of 4.5 and a height of 10.
A rectangle has length of 2x-5 units and a width of x-3 units what is the area in square units of the rectangle?
a rectangle has a length of 2x-5 units and a width of x-3 units. what is the area, in square units, of the rectangle?
What is the area of a rectangle with 2x and width 4x?
8x2 is.
The height is1 in less than twice the base the area is 22.5 sq in?
Presumably the question is about finding the height and base of a rectangle? If so then let the height be 2x-1 and the base be x: (2x-1)*x = 22.5 2x2-1x = 22.5 2x2-x-22.5 = 0 Solving the equation by using the quadratic equation formula will result in: x = -3.113406012 or x = 3.613406012 the dimensions can't be negative so the latter is the solution. Therfore: length = 6.226812024 inches and the base = 3.613406012 inches
A triangle has a base length of 2x 4 and a height of 3y Area 12bh so what is the area of the triangle?
i think basexheight and then divide 2
How do you find the area of a parallelogram if x plus 2 is the base and x is the height?
You expand x(x+2) which is x2+2x.
How do you find the area of a triangle whose base is 2x plus 3 and the height is 3x - 1?
You probably know that the area of any triangle is (1/2) x (base) x (height).Take that formula, substitute (2x+3) in the place where it says "base", andsubstitute (3x-1) in the place where it says "height". Then do the multiplication,and you'll have a tidy expression for the area of your triangle.Of course, it'll still have an "x" in it, as well as an "x2", but you should expect that.If the base and the height both depend on the value of 'x', then naturally the areamust also depend on the value of 'x'.
The length of a rectangle is twice its width If the perimeter of the rectangle is 60cm find its area?
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
Find the dimension of a rectangle with the least perimeter and the area fo 30 cm?
rectangle with 10" length and 2x-4 width 60" area
