If that means (2 times 4) then the area of the square is 8*8 = 64 square cm
Rectangular Prisim 2x(area of front)+2x(area of side)+x2(area of length) Cube 2x(area of side)+2x(area of side)+2x(area of side)
4x2 - 4xy + y2 = (2x - y)2 so the length of the side of the square must be 2x-y.
Perimeter of a square = 4 * sideP = 4 * (2x +1)P = 8x + 4
Area of square = x2Area of rectangle = 2x * (x-3)The two area are the same so x2 = 2x2 - 6xso x2 = 6xso x = 6The square has sides of length 6A+ = x2 = 2x2 - 6
Let the width = X. The length is twice the width plus 5. So the length must be 2X + 5. Area = 63 ft squared = X multiplied by 2X + 5 = 2X squared + 25. 2X squared = 63 - 25 = 38 2X = square root of 38. Therefore the width is the square root of 38 divided by 2 and the length is the square root of 38 plus 5.
The area is 4x2 square units
(2x-7)(2x-7) = area 4x2-28x+49 = area
It is: (2x-5)(2x-5) = 2.5 square cm when solved as a quadratic equation
Rectangular Prisim 2x(area of front)+2x(area of side)+x2(area of length) Cube 2x(area of side)+2x(area of side)+2x(area of side)
Each side of the square is 2x+1.5 and its area is (2x+1.5) squared
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The perimeter is the sum of the sides. So if a square has a side of length 1, its perimeter is 1+1+1=1 = 4 If a square has a side doubled to length 2, its perimeter is 2+2+2+2 = 8, or double what it was before. Mathematically, if each side is length x it perimeter is x + x + x = X = 4x If each side is length 2x, its perimeter is 2x +2x+2x+2x = 8x
4x2 - 4xy + y2 = (2x - y)2 so the length of the side of the square must be 2x-y.
2x*r2 square units where r is the radius and 2x is the angle (measured in radians).
Perimeter of a square = 4 * sideP = 4 * (2x +1)P = 8x + 4
4(2x+3) [there's 4 equal sides] 4(2x)+4(3) 8x+12