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Earn +20 ptsQ: What is the diagonal of 132 x 132?
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What is the product of two consecutive integers that equals 132?
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
How do you solve X2 plus x-132?
-130
What is the prime factorization of 132 using exponents?
22 x 3 x 11 = 132
What is a diagonal of 30' x 30'?
Pythagoras! Diagonal = sqrt (900 + 900) = 42.43'
What does 11x12 equal?
By Lomg Multiplication 12 x 11 120 ( 10 x 12 = 120) 12 ( 1 x 12 = 12) 132 ====
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