a root number is a number in which satifies the unknown value of an equation. For example: x² - 1 = 0 the root of this equation would be 1 or -1 since when multiplied by itself, they both equal 1. Therefore, 1 - 1 = 0
x^2-3x-28=0...................
If you mean: 9x squared+6x+1 = 0 then x = -1/3 and x = -1/3 therefore the quadratic equation has equal roots
It's equal to -X + 5 = Y (1, 4) (5, 0)
4x2 - 4x + 1 = 0 => (2x - 1)(2x - 1) = 0 => (2x - 1)2 = 0 There is one solution: x = 1/2. It is a repeated root of the equation.
Lots, eg x2 - 2x + 1 = 0 which factorises as (x - 1)(x - 1) = 0
a root number is a number in which satifies the unknown value of an equation. For example: x² - 1 = 0 the root of this equation would be 1 or -1 since when multiplied by itself, they both equal 1. Therefore, 1 - 1 = 0
Set the equation equal to zero. 3x2 - x = -1 3x2 - x + 1 = 0 The equation is quadratic, but can not be factored. Use the quadratic equation.
0
x+7y+4 = 0 => y = -1/7x-4/7 The slope of the second equation is the reciprocal of the first equation with the minus sign changing to a plus sign. y = mx+c where m is the slope and c is the intercept on the y axis So: 7*4+c = 0 28+c = 0 c = -28 Therefore the perpendicular equation is: y = 7x-28 which can be expressed in the form of 7x-y-28 = 0
The y-intercept is 0 and the slope is 1.
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
x^2-3x-28=0...................
Divide all terms by -2: 4x2+4x+1 = 0 (2x+1)(2x+1) = 0 x = -1/2 and also x = -1/2 The quadratic equation has 2 equal roots.
i think your a bit confused (or have written your question wrongly). n is an unknown (as you didnt state otherwise), and can take any value. n could equal 1 (1 squared -25*1 +84doesnt equal 0), therefore you cannot show that your expression equals 0. i assume you meant to ask us to solve the equation you gave (which would mean you are asking for the values of n, which satisfy the equation), so this is what i shall do. To solve this, as it is a quadratic equation, you first look to factorise (if this doesn't work, use the quadratic formula): To factorise the equation: n^2 - 25n + 84 = 0, you need to find two numbers which multiply to give +84, and add together to give -25. these numbers are -3 and -28 (by trial and error). therefore n^2 - 25n + 84 = (n-3)(n-28) = 0 and the only way two numbers multiply together to get 0, is if either (or both) numbers are 0. therefore: n - 3 = 0 which gives the solution n=3 or: n - 28 = 0 which gives the solution n=28 therfore the solutions are n=28 or n=3
There is no number that can multiplied by 0 to get 1. The equation 0x = 1 has no solution bcause 0x = 0 whatever number x may be. You might think that 1/0 times 0 would equal 1 but 1/0 is not a number.
y = ax + b x to the power of 1, x^1 there are no exponents in the simplified formula x is in the equation, so a does not equal 0 b can be any number