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That would depend on the given points more easily to define because they are open to different interpretations.
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What is the slope-intercept equation of the line that contains the points (1 2) and (0 -2)?
Points: (1, 2) and (0, -2) Slope: 4 Equation: y = 4x-2
What is the equation of the line that passes through the points 0 5 and 2 3?
Points: (0. 5) and (2, 3) Slope: -1 Equation: y = -x+5
Which equation represents the line that passes through 0 0 and is parallel to the line passing through 2 3 and 6 1?
The equation in slope-intercept form would be y=-2x
What equation of the line that contains the point 1 -1 and 2 -2?
Choose the equation of the line that contains the points (1, -1) and (2, -2).
What is the equation of a line in slope-intercept form for a line with slope 4 and y-intercept at (0 2)?
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
What is the equation of (0 -1) (1 1) (2 3)?
The slope of the line is 2 and its equation is y = 2x-1
What is The graph of a line passes through the points (0 -2) and (6 0). What is the equation of the line?
Points: (0, -2) and (6, 0) Slope: 1/3 Equation of line: 3y = x-6
What is the equation of the line passing through the points 0 2 and 60?
Points: 0 2 and 6 0 Equation: y = -1/3x+2
What is the slope-intercept equation of the line that contains the points (1 2) and (0 -2)?
Points: (1, 2) and (0, -2) Slope: 4 Equation: y = 4x-2
What is the equation of a line that passes through the point 0 2 and is perpendicular to a line with a slope of 3?
Slope of line: 3 Perpendicular slope: -1/3 Equation: y-2 = -1/3(x-0) => y = -1/3x+2
A line passes through the points 0-1 and 2 3 What is the equation for the line?
Suppose the equation of the line is y = mx + c. (0,-1) is on this line so -1 = m*0 + c ie -1 = c so y = mx - 1 Also, (2,3) is on the line so 3 = m*2 - 1 or 2m = 4 so m = 2 So the equation of the line is y = 2x - 1
What is the equation of a line that passes through points (0 -1) and (2 3)?
As Slope=m=3-(-1)/2-0=2 So equation is y-(-1)=2×(x-0) y+1=2x 2x-y-1=0
What is the equation of a line through point 1 0 that has a slope of -2?
y-0 = -2(x-1) y = -2x+2
What is the equation of the line from the origin to the middle of the line with endpoints at 3 2 and 5 -1 on the Cartesian plane?
Endpoints: (3, 2) and (5, -1) Midpoint: (4, 0.5) Slope of line from (0, 0) to (4, 0.5) = 1/8 Equation of line: y = 1/8x
What is the equation to a line with an x interceptof -1 and a y intercept of 2?
X intercept of -1 means that the line passes through (-1,0) y intercept of 2 means that the line passes though (0,2) The equation of this line is (y - y1) = [(y2 - y1)/(x2 - x1)] x (x - x1), that is y - 0 = [(2 - 0)/(0 + 1)] x (x +1), that is y = (2) x (x +1) or y = 2x + 2 Verification: In the equation y = 2x + 2 1) substitute -1 for x and y evaluates to 0; 2) substitute 0 for x in the equation and you get y as 2 which means this line passes through (-1,0) and (0,2)
What is the equation of the line that connects the points 0 1 to 1 0 and its distance on the Cartesian plane?
Points: (0, 1) and (1, 0) Slope: -1 Equation: y = -x+1 Distance: square root of 2
What is the equation of a line in general form that passes through points (-1 2) and (5 2)?
Points: (-1, 2) and (5, 2) Slope: 0 Equation: y = 2
