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That would depend on the given points more easily to define because they are open to different interpretations.

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Q: What is the equation of this line 0 -1 1 1 2 3?
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What is the equation of (0 -1) (1 1) (2 3)?

The slope of the line is 2 and its equation is y = 2x-1


What is The graph of a line passes through the points (0 -2) and (6 0). What is the equation of the line?

Points: (0, -2) and (6, 0) Slope: 1/3 Equation of line: 3y = x-6


What is the equation of the line passing through the points 0 2 and 60?

Points: 0 2 and 6 0 Equation: y = -1/3x+2


What is the slope-intercept equation of the line that contains the points (1 2) and (0 -2)?

Points: (1, 2) and (0, -2) Slope: 4 Equation: y = 4x-2


A line passes through the points 0-1 and 2 3 What is the equation for the line?

Suppose the equation of the line is y = mx + c. (0,-1) is on this line so -1 = m*0 + c ie -1 = c so y = mx - 1 Also, (2,3) is on the line so 3 = m*2 - 1 or 2m = 4 so m = 2 So the equation of the line is y = 2x - 1


What is the equation of a line that passes through the point 0 2 and is perpendicular to a line with a slope of 3?

Slope of line: 3 Perpendicular slope: -1/3 Equation: y-2 = -1/3(x-0) => y = -1/3x+2


What is the equation of a line that passes through points (0 -1) and (2 3)?

As Slope=m=3-(-1)/2-0=2 So equation is y-(-1)=2×(x-0) y+1=2x 2x-y-1=0


What is the equation of a line through point 1 0 that has a slope of -2?

y-0 = -2(x-1) y = -2x+2


What is the equation of the line from the origin to the middle of the line with endpoints at 3 2 and 5 -1 on the Cartesian plane?

Endpoints: (3, 2) and (5, -1) Midpoint: (4, 0.5) Slope of line from (0, 0) to (4, 0.5) = 1/8 Equation of line: y = 1/8x


What is the equation to a line with an x interceptof -1 and a y intercept of 2?

X intercept of -1 means that the line passes through (-1,0) y intercept of 2 means that the line passes though (0,2) The equation of this line is (y - y1) = [(y2 - y1)/(x2 - x1)] x (x - x1), that is y - 0 = [(2 - 0)/(0 + 1)] x (x +1), that is y = (2) x (x +1) or y = 2x + 2 Verification: In the equation y = 2x + 2 1) substitute -1 for x and y evaluates to 0; 2) substitute 0 for x in the equation and you get y as 2 which means this line passes through (-1,0) and (0,2)


What is the equation of the line that connects the points 0 1 to 1 0 and its distance on the Cartesian plane?

Points: (0, 1) and (1, 0) Slope: -1 Equation: y = -x+1 Distance: square root of 2


What is the equation of a line in general form that passes through points (-1 2) and (5 2)?

Points: (-1, 2) and (5, 2) Slope: 0 Equation: y = 2