It is: (x+4)(x-2) when factored
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x3 + 8 = x3 + 23 = (x + 2)[x2 - (x)(2) + 22] = (x + 2) (x2 - 2x + 4)
X2 + 2X - 14 = 6X2 + 2X - 8 = 0what two products of - 8 = 2 ?(X +4)(X - 2)=========X = - 4X = 2
X3 + 8= (x+2)(x2-2x+4)
x2 + 12x + 32 = (x + 8)(x + 4)
x2 + 3x - 40 = (x + 8)(x - 5)