Try Un = n2
Try Un = n2
Try Un = n2
Try Un = n2
2(n-1)
> since the value rises by nine at each step and the first term is 12 the formula for > the nth term is: 12+(n-1)*9 Which simplifies to Sn = 9n + 3
It is: nth term = 29-7n
n-squared, or n to the power 2
The nth term is 4n-1 and so the next term will be 19
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
tn = n2
Tn = 1 + 3n
The Nth term formula for oblong numbers is N = N(N+1)
It is: nth term = 35-9n
The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
The nth term is: 5-6n
To determine the nth term of the sequence 25, 16, 7, we first identify the pattern. The sequence appears to be decreasing by 9, then by 9 again, suggesting a consistent difference. This leads to a formula for the nth term: ( a_n = 34 - 9n ), where ( a_1 = 25 ) for n=1. Thus, the nth term can be expressed as ( a_n = 34 - 9n ).
The given sequence is an arithmetic sequence where each term decreases by 5. The first term (a) is -1 and the common difference (d) is -5. The nth term can be calculated using the formula ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = -1 + (n-1)(-5) = -1 - 5(n-1) = -5n + 4 ).
The sequence provided is an arithmetic sequence where each term increases by 3. The first term (a) is 1, and the common difference (d) is 3. The nth term can be calculated using the formula: ( a_n = a + (n - 1) \cdot d ). Therefore, the nth term is ( a_n = 1 + (n - 1) \cdot 3 = 3n - 2 ).
The sequence given is -2, 4, -8, 16, which can be observed as alternating signs with each term being a power of 2 multiplied by -1. The nth term can be expressed as ( a_n = -2 \times (-2)^{n-1} ), or equivalently, ( a_n = -2^n ) if you account for the sign change. Thus, the nth term formula is ( a_n = -2^n ).
The nth term is: 3n+1 and so the next number will be 16