There are infinitely many possible answers. Given ANY number, it is always possible to find a polynomial of order 5 [at most] that can be used as the nth term rule for the given five number and the additional sixth. There are also non-polynomial solutions. Each different sixth number will result in a different polynomial and, since there are infinitely many sixth numbers, there are infinitely many answers to the question.
Having said that, the simplest polynomial solution is Un = 9n - 2
The nth term rule of the sequence 11, 20, 29, 38, 47 is given by the formula (a_n = 11 + 9(n-1)), where n represents the position of the term in the sequence. In this formula, 11 is the first term of the sequence, and 9 is the common difference between consecutive terms. By substituting the position of the term (n) into the formula, you can find the value of the nth term in the sequence.
Ah, let's take a moment to appreciate the beauty of patterns in numbers. To find the nth term rule of this sequence, we can see that each number increases by 9. So, the nth term rule is n x 9 + 2. Just like painting a happy little tree, finding patterns in numbers can bring a sense of joy and satisfaction.
Given n and any number for the nth term, it is a simple matter to find a rule such that the above four numbers are the first four of a sequence and the given number in the nth position.However, the simple answer for simple questions is Un = 4n
720
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
The first term is 10. Dividing (say) the 3rd term by the 2nd term gives 40/20 = 2 Dividing any two successive terms in this manner results in the same answer. Then 2 is the common ratio. The general formula for the nth term of a Geometric Progression or Series is :- a(n) = ar^n-1.....where a is the first term and r is the common ratio. For the pattern provided, a(n) = 10 x 2^n-1
Well, darling, the first 5 terms in that fancy sequence are 28, 26, 24, 22, and 20. You get those numbers by plugging in n values 1 through 5 into the formula 30-2n. So, there you have it, sweet cheeks!
The nth term is: 3n+2 and so the next number will be 20
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
20-9x=n
a (sub n) = 11 + (n - 1) x d
20 - (3 * (n - 1))
Given n and any number for the nth term, it is a simple matter to find a rule such that the above four numbers are the first four of a sequence and the given number in the nth position.However, the simple answer for simple questions is Un = 4n
Un = 29 - 9n
The nth term of the sequence is expressed by the formula 8n - 4.
They are: nth term = 6n-4 and the 14th term is 80
560
As can be seen, each succesive term is 2 greater than the last. We can write a rule to calculate the nth term. Here the rule equals 2n - 8. So the 20th term = (2 * 20) - 8 = 32.
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...