There are infinitely many possible answers. Given ANY number, it is always possible to find a polynomial of order 5 [at most] that can be used as the nth term rule for the given five number and the additional sixth. There are also non-polynomial solutions. Each different sixth number will result in a different polynomial and, since there are infinitely many sixth numbers, there are infinitely many answers to the question.
Having said that, the simplest polynomial solution is Un = 9n - 2
Given n and any number for the nth term, it is a simple matter to find a rule such that the above four numbers are the first four of a sequence and the given number in the nth position.However, the simple answer for simple questions is Un = 4n
720
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
Oh, dude, finding the nth term for this pattern is like finding your favorite socks in the laundry - tedious but doable. So, to get from 10 to 20, you multiply by 2, then by 2 again to get 40, then 80, then 160. So, the pattern is just doubling each time. That means the nth term is 10 times 2 to the power of n-1. Easy peasy!
20th term = 20*(20+1)/2
The nth term is: 3n+2 and so the next number will be 20
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
20-9x=n
a (sub n) = 11 + (n - 1) x d
20 - (3 * (n - 1))
Given n and any number for the nth term, it is a simple matter to find a rule such that the above four numbers are the first four of a sequence and the given number in the nth position.However, the simple answer for simple questions is Un = 4n
Un = 29 - 9n
We note that there are a difference of '9' between terms . Hence '9n' Next find the constant 'c' 1st term ; 9(1) + c = 20 => c = 11 2 nd term ; 9(2) + c = 29 => c = 11 nth term is 9n + 11 e.g. 7th term is 9(7) + 11 = 63 + 11 = 74
The nth term of the sequence is expressed by the formula 8n - 4.
They are: nth term = 6n-4 and the 14th term is 80
560
As can be seen, each succesive term is 2 greater than the last. We can write a rule to calculate the nth term. Here the rule equals 2n - 8. So the 20th term = (2 * 20) - 8 = 32.