The integral of X 4Y X 8Y 2 With respect to X is 2ln(10/9).
14
when y = 3, 8y-4y = 4y = 4*3 = 12
y2 + 8y + 16 = y2 + 4y + 4y + 16 = y(y + 4) + 4(y + 4) = (y + 4)(y + 4) or (y + 4)2
16y^2(8y)=0? Factor out an 8y to give you 8y(2y(2))=0 Use order of operations to give you 8y(4y)=0 Distribute to give you 32y=0 and ultimately the answer will be 0 If there is a missing plus or minus operator between 16y2 and the 8y, then it can be factorised by taking out common factors: 16y2 ± 8y = 0 ⇒ 8y(2y ± 1) = 0
2x + 8y --- has a GCF of 2= 2(x + 4y)
The integral of X 4Y X 8Y 2 With respect to X is 2ln(10/9).
15d+12y-4y+5d 15d+5d+12y-4y 20d+8y
14
3
12y-7
8y - 38
5x - 4y ≥ -203x - 2y ≤ -8y ≥ -3
when y = 3, 8y-4y = 4y = 4*3 = 12
It cannot be done using real numbers. However, it can be done using complex numbers: 16y² + 4y + 1 = ¼(8y + (1 + i√3))(8y + (1 - i√3))
( 2xy - 4x ) + ( 8y - 16)2 ( xy - 2x ) + 2 ( 4y - 8 ) Answer
3x - 4y = 8Solve for x:3x = 4y + 8x = 4/3y + 8/3Solve for y:-4y = -3x + 8y = 3/4x - 2