4y + 8y = 12y
4y - 8y = -4y
4y x 8y = 32y2
4y/8y = 1/2
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The integral of X 4Y X 8Y 2 With respect to X is 2ln(10/9).
14
when y = 3, 8y-4y = 4y = 4*3 = 12
y2 + 8y + 16 = y2 + 4y + 4y + 16 = y(y + 4) + 4(y + 4) = (y + 4)(y + 4) or (y + 4)2
16y^2(8y)=0? Factor out an 8y to give you 8y(2y(2))=0 Use order of operations to give you 8y(4y)=0 Distribute to give you 32y=0 and ultimately the answer will be 0 If there is a missing plus or minus operator between 16y2 and the 8y, then it can be factorised by taking out common factors: 16y2 ± 8y = 0 ⇒ 8y(2y ± 1) = 0