Oh, dude, isolating y2 in an equation just means getting y2 by itself on one side. It's like setting it free from the other numbers, giving it some space to breathe. So, you'd probably end up with something like y2 = (other stuff), and y2 would be like, "Finally, I can be me without all these other numbers holding me back."
y2=-x2-8x+6
(x-2)^2+y^2=64
y2 = 169 Square root both sides: y = 13
y2=x3+3x2
y=±√15
y2=-x2-8x+6
(x-2)^2+y^2=64
To isolate ( y^2 ) in the equation, you would typically perform algebraic operations to rearrange the equation. For example, if the equation is in the form ( ax^2 + by^2 = c ), you would first move the other terms to one side to get ( by^2 = c - ax^2 ), and then divide by ( b ) to isolate ( y^2 ), resulting in ( y^2 = \frac{c - ax^2}{b} ). If you provide a specific equation, I can give a more tailored answer.
4
9 (APEX)
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
1
11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2
5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.
t
x2 + y2 =x2 + y2 = 5x2 + y2 = 10x2 + y2 = 25
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.