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Oh, dude, isolating y2 in an equation just means getting y2 by itself on one side. It's like setting it free from the other numbers, giving it some space to breathe. So, you'd probably end up with something like y2 = (other stuff), and y2 would be like, "Finally, I can be me without all these other numbers holding me back."
What else can I help you with?
What is the result of isolating y2 in the equation below (x plus 4) plus y2 22?
y2=-x2-8x+6
What is the result of isolating y2 (x - 2)2 y2 64?
(x-2)^2+y^2=64
The curve with equation y2 equals x3 plus 3x2 is called the Tschirnhausen cubic?
y2=x3+3x2
What are the solutions to the equation y2 equals 169?
y2 = 169 Square root both sides: y = 13
Solve the quadratic equation y2-15 equals 0?
y=±√15
What is the result of isolating y2 in the equation below (x plus 4) plus y2 22?
y2=-x2-8x+6
What is the result of isolating y2 (x - 2)2 y2 64?
(x-2)^2+y^2=64
What is the result of isolating y2 in the equation below (x-2)2 y264?
To isolate ( y^2 ) in the equation ( (x-2)^2 y^2 = 64 ), you first divide both sides by ( (x-2)^2 ). This gives you ( y^2 = \frac{64}{(x-2)^2} ). Thus, the result is ( y^2 = \frac{64}{(x-2)^2} ).
What is the result of isolating y2 in th equation below?
To isolate ( y^2 ) in the equation, you would typically perform algebraic operations to rearrange the equation. For example, if the equation is in the form ( ax^2 + by^2 = c ), you would first move the other terms to one side to get ( by^2 = c - ax^2 ), and then divide by ( b ) to isolate ( y^2 ), resulting in ( y^2 = \frac{c - ax^2}{b} ). If you provide a specific equation, I can give a more tailored answer.
The equation for the circle below is x2 plus y2 16. What is the length of the circle's radius?
4
The equation for the circle below is x2 plus y2 81. What is the length of the circle's radius?
9 (APEX)
The circle is centered at the origin and the length of its radius is 8 What is the circle's equation?
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
What equation is 3x-y2?
1
What is the result of isolating y2 in the equation below 9x2 plus 7y2 42?
To isolate ( y^2 ) in the equation ( 9x^2 + 7y^2 = 42 ), first subtract ( 9x^2 ) from both sides: ( 7y^2 = 42 - 9x^2 ). Then, divide both sides by 7: ( y^2 = \frac{42 - 9x^2}{7} ). Thus, the isolated form of ( y^2 ) is ( y^2 = 6 - \frac{9}{7}x^2 ).
The equation for the circle below is x2 plus y2 equals 121 What is the length of the circles radius?
11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2
What the radius for a circle with the equation x2 plus y2 equals 25?
5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.
Is y2-3x a linear equation?
t
