Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y^2 or (x + y)^2.
Without any equality signs the given expressions can't be considered as equations.
the system of equations 3x-6y=20 and 2x-4y =3 is?Well its inconsistent.
If you mean: 6x+6y = 36 and 2x-2y = 20 then its works out x = 8 and y = -2
Linear algebra is used to analyze systems of linear equations. Oftentimes, these systems of linear equations are very large, making up many, many equations and are many dimensions large. While students should never have to expect with anything larger than 5 dimensions (R5 space), in real life, you might be dealing with problems which have 20 dimensions to them (such as in economics, where there are many variables). Linear algebra answers many questions. Some of these questions are: How many free variables do I have in a system of equations? What are the solutions to a system of equations? If there are an infinite number of solutions, how many dimensions do the solutions span? What is the kernel space or null space of a system of equations (under what conditions can a non-trivial solution to the system be zero?) Linear algebra is also immensely valuable when continuing into more advanced math topics, as you reuse many of the basic principals, such as subspaces, basis, eigenvalues and not to mention a greatly increased ability to understand a system of equations.
It looks like you have 2 simultaneous equations with 2 variables:4x + 8y = 20 and -4x + 2y = -30. Solution is {x=7, y = -1}.One way to solve:Add the two equations together, combining like terms: (4x - 4x) + (8y + 2y) = 20-30 --> 0 + 10y = -10 --> y = -1. Substitute this into either of the original equations and solve for x=7, then check in the other equation to make sure you calculated correctly.
Without any equality signs the given expressions can't be considered as equations.
Here are some practice problems for systems of equations: Solve the following system of equations: 2x 3y 10 4x - y 5 Find the solution to the system of equations: 3x 2y 12 x - y 3 Determine the values of x and y that satisfy the system of equations: 5x 4y 20 2x - 3y 1 Hope these help with your practice!
the system of equations 3x-6y=20 and 2x-4y =3 is?Well its inconsistent.
the solution to the system of equations 6x + 7y = 20 and y = 2x is (x, y) = (1, 2)
If you mean: 6x+6y = 36 and 2x-2y = 20 then its works out x = 8 and y = -2
It is not possible to know exactly what the question is because the browser used by this site is almost totally useless for mathematical questions: it rejects most symbols. If the equations are 2y + 2x = 20 and y - 2x = 4,then the solution is (2, 8).
To find two numbers that add to 20 and multiply to 29, we can set up a system of equations. Let's call the two numbers x and y. We have the following equations: x + y = 20 and x * y = 29. By solving these equations simultaneously, we find that the two numbers are 5 and 15.
Let x be the liters of the 30% acid solution and y be the liters of the 60% acid solution. We can set up a system of equations: x + y = 50 (total liters) and 0.3x + 0.6y = 0.57*50 (acid content). Solving this system of equations, we find that x = 20 liters of the 30% acid solution and y = 30 liters of the 60% acid solution.
Let there be x litres of 50% solution and y% of 20 % solution, then you have two equations by considering the amount of alcohol and the total amount of liquid:50% x + 20% y = 40% of 3 litresx + y = 3 litresThese are two simultaneous equations involving 2 unknowns which can be solved:Double {1} and subtract from {2} to give:x - x + y - 40%y = 3 - 80% of 3→ 60% y = 20% of 3→ y = 20%/60% of 3 = 1/3 of 3 = 1Substitute for y in {2} to get:x + 1 = 3x = 2Therefore you need 2 litres of 50% solution and 1 litre of 20% solution.
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Linear algebra is used to analyze systems of linear equations. Oftentimes, these systems of linear equations are very large, making up many, many equations and are many dimensions large. While students should never have to expect with anything larger than 5 dimensions (R5 space), in real life, you might be dealing with problems which have 20 dimensions to them (such as in economics, where there are many variables). Linear algebra answers many questions. Some of these questions are: How many free variables do I have in a system of equations? What are the solutions to a system of equations? If there are an infinite number of solutions, how many dimensions do the solutions span? What is the kernel space or null space of a system of equations (under what conditions can a non-trivial solution to the system be zero?) Linear algebra is also immensely valuable when continuing into more advanced math topics, as you reuse many of the basic principals, such as subspaces, basis, eigenvalues and not to mention a greatly increased ability to understand a system of equations.
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