Given the equation x2 - x - 20 = 0, we see that it can likely be factored easily. Through simple trial and error we find that:
(x - 5)(x + 4) = 0.
From here, we set both terms equal to zero to find all possible solutions.
x - 5 = 0
x = 5
and
x + 4 = 0
x = -4.
Substituting 5 and -4 back into the original equation yield true results. Thus the solution set is x = -4, 5. More formal, the solution set is {-4, 5}.
Note: There are other methods of solving this problem such as the quadratic formula or by graphing the function.
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Not sure about the set builder notation, but Q = {0}, the set consisting only of the number 0.
Using the quadratic formula, I found the solution set is x=2,x=-9
Yes it is!
do it yourself
You could graph this Polynomial by using substution to solve for two points..which will define a line. If x=16, then y=0, If x=0, then y=8. Graph this line and you have the solution set for the equation.
a = [ 0, 4 ]
x-2y=0 x=2y The solution set is the set of all (x,y) such that x=2y
x = 0 or x = 2
(0, -14)
'x' must be zero, so the solution set is [ 0 ].
(-2,-1)
17
Not sure about the set builder notation, but Q = {0}, the set consisting only of the number 0.
Using the quadratic formula, I found the solution set is x=2,x=-9
7 and (-3/2)
x2 + 49 = 0 ∴ x2 = -49 ∴ x = 7i
r=0 is the solution...