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Q: What is the solution to the inequality x2 equals 16?

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The question cannot be answered because there is no inequality there!

do it yourself

It could be the solution to some quadratic inequalities: for example x2 + 2x - 3 > 0 whose solution is x < -3 or x > 1.

11-x2=-5 add -11 to both sides: 11-x2-11=-5-11 -x2=-16 divide both sides by -2: (-x2)/(-2)=(-16)/(-2) x=8 If the "x2" was supposed to be "x2", meaning exponentiation, ("x squared") and not "x2", implying multiplication, ("x times two") then we'd get: x2=16 x=±4

Using the quadratic formula, I found the solution set is x=2,x=-9

Related questions

x2≤64

if x2 ≠ 16, then: {x | x ∈ ℜ, x ∉ (4, -4)}

-4 and 4

x2 = 16take the root square for both sides the result will be :X = +4 or -4

x^2<25

the answer is -8<x<8.

The question cannot be answered because there is no inequality there!

If x2 < 25 Then: |x| < 5 -5 < x < 5

x2 â‰¥ 0 is one possible answer.

I will assume you mean,X2 - 16 = 0X2 = 16take square root each sideX = (+/-) 4=========(-4, 0) and (4, 0)----------------------

Yes. Consider x2 â‰¥ 0

(x-4)(x+4) = 0 x = 4 or x = -4

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