The question cannot be answered because there is no inequality there!
If x2 < 25 Then: |x| < 5 -5 < x < 5
do it yourself
It could be the solution to some quadratic inequalities: for example x2 + 2x - 3 > 0 whose solution is x < -3 or x > 1.
11-x2=-5 add -11 to both sides: 11-x2-11=-5-11 -x2=-16 divide both sides by -2: (-x2)/(-2)=(-16)/(-2) x=8 If the "x2" was supposed to be "x2", meaning exponentiation, ("x squared") and not "x2", implying multiplication, ("x times two") then we'd get: x2=16 x=±4
x2≤64
if x2 ≠ 16, then: {x | x ∈ ℜ, x ∉ (4, -4)}
-4 and 4
x2 = 16take the root square for both sides the result will be :X = +4 or -4
the answer is -8<x<8.
The question cannot be answered because there is no inequality there!
If x2 < 25 Then: |x| < 5 -5 < x < 5
x2 ≥ 0 is one possible answer.
If you meant x2 = 16 then take square root both sides which gives x = 4 but you need to see that -42 is also 16 so that is another solution. The two solutions are 4 and -4.
Yes. Consider x2 ≥ 0
x2 + 49 = 0 ∴ x2 = -49 ∴ x = 7i
do it yourself