x2≤64
x2 ≥ 0 is one possible answer.
Yes - except in extreme cases. It can be the whole of the Real Numbers: eg x2 > -3 It can be a single point eg x2 ≤ 0 gives x = 0
Without further information, the only inequality is x2 ≥ 0 (assuming x is real). In the complex domain, there is no inequality.
9x2+x+64 9*64=576 To skip all this confusion, I graphed it and it does not have a solution. When you graph it, it should cross the x-axis. When it does, the two places that it does is the solution.
x2≤64
If x2 < 25 Then: |x| < 5 -5 < x < 5
if x2 ≠ 16, then: {x | x ∈ ℜ, x ∉ (4, -4)}
The question cannot be answered because there is no inequality there!
x2 ≥ 0 is one possible answer.
The solution to the inequality x^2 > 36 can be found by first determining the values that make the inequality true. To do this, we need to find the values of x that satisfy the inequality. Since x^2 > 36, we know that x must be either greater than 6 or less than -6. Therefore, the solution to the inequality x^2 > 36 is x < -6 or x > 6.
Yes. Consider x2 ≥ 0
If x2 = 16 then this is not written as an inequality.An inequality tells us that one thing is not equal to another.The above is an equation, because it is telling us that one thing is equal to another.If x2 = 16 then x = 4 & -4.
Yes - except in extreme cases. It can be the whole of the Real Numbers: eg x2 > -3 It can be a single point eg x2 ≤ 0 gives x = 0
Without further information, the only inequality is x2 ≥ 0 (assuming x is real). In the complex domain, there is no inequality.
It could be the solution to some quadratic inequalities: for example x2 + 2x - 3 > 0 whose solution is x < -3 or x > 1.
9x2+x+64 9*64=576 To skip all this confusion, I graphed it and it does not have a solution. When you graph it, it should cross the x-axis. When it does, the two places that it does is the solution.