Yes. Consider x2 ≥ 0
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An inequality, like an equation, can have a different number of solutions depending on the inequality and the domain.For example, x2< 0 has no solutions if the domain is the real numbers.x< 5 has only one solution ( = 4) if the domain consists of the squares of positive even numbers.x < 5 has infinitely many solutions if the domain is the rational numbers or real numbers.An inequality, like an equation, can have a different number of solutions depending on the inequality and the domain.For example, x2< 0 has no solutions if the domain is the real numbers.x< 5 has only one solution ( = 4) if the domain consists of the squares of positive even numbers.x < 5 has infinitely many solutions if the domain is the rational numbers or real numbers.An inequality, like an equation, can have a different number of solutions depending on the inequality and the domain.For example, x2< 0 has no solutions if the domain is the real numbers.x< 5 has only one solution ( = 4) if the domain consists of the squares of positive even numbers.x < 5 has infinitely many solutions if the domain is the rational numbers or real numbers.An inequality, like an equation, can have a different number of solutions depending on the inequality and the domain.For example, x2< 0 has no solutions if the domain is the real numbers.x< 5 has only one solution ( = 4) if the domain consists of the squares of positive even numbers.x < 5 has infinitely many solutions if the domain is the rational numbers or real numbers.
The answer depends on what the factors will be. For example, every quadratic can be factored if you allow complex numbers. If not, then it helps to use the discriminant. If it is positive, there are two real factors or solutions. If that positive number is a perfect square, then the factors are rational numbers. If not, they are real but not rational (irrational). If the discriminant is 0, there is one real solution. Lastly, if it is negative, there are no real solutions.
It has one real solution.
No. A quadratic may have two identical real solutions, two different real solutions, ortwo conjugate complex solutions (including pure imaginary).It can't have one real and one complex or imaginary solution.
Suppose the quadratic equation is ax^2 + bx + c = 0 and D = b^2 - 4ac is the discriminant. Then the solutions to the quadratic equation are [-b ± sqrt(d)]/(2a). Since D = 0, the both solutions are equal to -b/(2a), a single real solution.