Using the standard form y = mx + c
Where m = slope of '2'
The point ( 5,-6) is displaced against ( x,y)
Hence
y - - 6 = 2(x - 5) Note the 'double' negative.
y + 6 = 2x - 10
y = 2x - 16
The standard form is: 2x - y - 16 = 0
If the slope is undefined, it is a vertical line. Therefore the equation is x=2.
If you mean a point of (-1, 4) and a slope of -3 then the equation is y = -3x+1
If you mean passing through (1, 2) with a slope of -3 then it is y = -3x+5
y = 1/3x+4/3
7
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
If the slope is undefined, it is a vertical line. Therefore the equation is x=2.
If you mean a point of (-1, 4) and a slope of -3 then the equation is y = -3x+1
what
It is the equation of a line passing through the point (0, 1/3) and with slope 4/3
If you mean passing through (1, 2) with a slope of -3 then it is y = -3x+5
It is: y = 5x+6
The standard form is: 5x - y + 4 = 0
y = 1/3x+4/3
If you mean a point of (0, 3) and a slope of 2 then the equation is y = 2x+3
If you mean: y = -x-3 passing through point of (-1, 3) Then the equation of the parallel line is: y =-x+2