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Using the standard form y = mx + c

Where m = slope of '2'

The point ( 5,-6) is displaced against ( x,y)

Hence

y - - 6 = 2(x - 5) Note the 'double' negative.

y + 6 = 2x - 10

y = 2x - 16

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lenpollock

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1y ago
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8y ago

The standard form is: 2x - y - 16 = 0

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Q: What is the standard form of the equation of the line with slope 2 passing through the point 5 -6?
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