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What is the sum of all 3 digit positive integers that can be formed using the digits 1 5 and 8 if the digits are allowed to repeat within a number?
Wiki User
∙ 14y ago
111+115+118+151+155+158+181+185+188+511+515+518+551+555 +558+581+585+588+811+815+818+851+855+858+881+885+888 = 13,986.
Wiki User
∙ 14y ago
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When the negative integers the positive integers and 0 are combined the integers are formed?
Negative integers, zero and the positive integers, together form the set of integers.
How many different positive integers can be formed if the first digit must be 2 the last digit cannot be 0 and digits may be repeated?
1 x 10 x 10 x 10 x 9 = 9000 1 = it must be 2 10's = any digits 9 = any digit BUT zero
How many 4 digit numbers can be formed using the digits 0 1 2 3 4 5 6 7 8 9 if repetitions of digits are allowed?
10,000
How many 3 digit numbers can be formed using the digits 2 3 5 6 7 9 if repetition of digits is not allowed?
120 There are 6 digits in total. The numbers with 3 digits, with all digits distinct from each other, are the permutations of the 6 digits taken 3 at a time, and therefore there are 6*5*4 = 120 of them.
How many 6 digit numbers can be formed using the digits 0 1 2 3 4 5 6 7 8 9 if repetitions of digits are allowed?
There are 10 numbers in all including 0. The first space can be filled in 9 ways (as we have to exclude 0). The second through sixth spaces can be filled in 10 ways as 0 can be included. Totally, 9 x 10 x 10 x 10 x 10 x 10 or 9 x 10^5 digits can be formed if repetition is allowed.
How many different positive integers less than 2000 can be formed by using digits 123 and 4?
64 if repetition is allowed, 6 otherwise.64 if repetition is allowed, 6 otherwise.64 if repetition is allowed, 6 otherwise.64 if repetition is allowed, 6 otherwise.
When the negative integers the positive integers and 0 are combined the integers are formed?
Negative integers, zero and the positive integers, together form the set of integers.
How many 6 digit numbers can be formed with 1 to 45 digits?
Assuming all 45 digits are different (which they will not be if they are ordinary integers), then 456, if repetitions are allowed. That is 8303765625. If repetitions are not allowed then the number falls to 45*44*43*42*41*40 = 5864443200
How many different positive four digit integers can be formed if the first digit must be even the last digit must be odd and all digits must be distinct?
There are 320 such numbers.
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many numbers of 3 digits and less than 500 can be formed from the integers 3 4 5 and 9 if the digits must be different?
12 numbers.
How many 3 digit numbers can be formed from the digits 1234?
64 if repetition is allowed.24 if repetition is not allowed.
How many 3 digits odd numbers can be formed from the digits 1 2 3 4 and 5 if repetition is not allowed?
125
How many 5 digits can be formed using the digits 0 2 3 4 5 when repetition is allowed that the number formed is divisible by 2 and 5 or both?
There are 2000 such numbers.
How many four digit numbers can be formed from the digits 1 and 2 if repetitions are allowed?
pizza
How many even number of 4 digits can be formed out of digits 12.9 if repition of digit is not allowed?
Assuming the question refers to the digits 1, 2, ... , 9 the answer is 1344 numbers.
How many numbers of at least tree different digits can be formed from the integers 123456?
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
