so let's group and then factor ab+2a+3b+6= (ab+2a)+(3b+6)= a(b+2)+3(b+2)= (a+3)(b+2) and that is our final answer! Doctor Chuck
(a x b)^b =ab x b^2 =ab^3
a+b(a+B)=ab
log AB^2 log A+log B+log2
A^2-2ab+B^2 is actually (A+B)^2 AB squared is A^2B^2 or (AB)^2
a=7 b=9 ab=? ab is the multiplication of a & b there fore the value of ab=7*9=63
15
30 + ab + 6b + 5a = 5(a+6) + b(a+6) = (b+5)(a+6)
BS
ab means that a is multiplied (times) by b and then 6 is subtracted from the answer. So if the question says "If a = 5 and b = 4, what does ab - 6 =?" then you multiply 5 x 4 = 20 and subtract 6. So the answer is 14.
so let's group and then factor ab+2a+3b+6= (ab+2a)+(3b+6)= a(b+2)+3(b+2)= (a+3)(b+2) and that is our final answer! Doctor Chuck
By the definition of "reciprocal", any fraction multiplied by its reciprocal is equal to 1. For example:2/3 x 3/2 = 6/6 = 1a/b x b/a = ab/ab = 1By the definition of "reciprocal", any fraction multiplied by its reciprocal is equal to 1. For example:2/3 x 3/2 = 6/6 = 1a/b x b/a = ab/ab = 1By the definition of "reciprocal", any fraction multiplied by its reciprocal is equal to 1. For example:2/3 x 3/2 = 6/6 = 1a/b x b/a = ab/ab = 1By the definition of "reciprocal", any fraction multiplied by its reciprocal is equal to 1. For example:2/3 x 3/2 = 6/6 = 1a/b x b/a = ab/ab = 1
b
The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.It gets a lot more complicated in the latter case if they can be non-integers.The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.It gets a lot more complicated in the latter case if they can be non-integers.The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.It gets a lot more complicated in the latter case if they can be non-integers.The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.It gets a lot more complicated in the latter case if they can be non-integers.
30
Ab+ universal receiver o- universal donor blood types: can donate to: can receive from: ab+: ab+: ab+ ab- a+ a- b+ b- o+ o- ab-: ab+ ab-: ab- b- a- o- a+: a+ ab+: a+ a- o+ o- a-: a+ a- ab+ ab-: a- o- b+: b+ ab+: b+ b- o+ o- b-: b- b+ ab- ab+: b- o- 0+: o+ a+ b+ ab+: o- o+ o-: o+ o- a+ a- b+ b- ab+ ab-: o-
(a x b)^b =ab x b^2 =ab^3